Put thes fallowing numbers in order from largest to smallest -3, -3.5, 6, -6, 0, 1

Mathematics

2 answers:

densk [106]3 years ago

8 0

Answer:

6,1,0,-3,-3.5,-6

Step-by-step explanation:

Verdich [7]3 years ago

5 0

6, 1, 0, -3, -3.5, -6

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asambeis [7]

Answer:

The sum of 2 and the quotient of 3 and y

Step-by-step explanation:

The expression 2 + 3/y without any parentheses is evaluated as ...

2 + (3/y)

which is a sum. The first contributor to the sum is 2, and the second contributor is the quotient of 3 and y. (Usually, "the quotient of "a" and "b" means "a/b".)

Hence the answer shown above is a good description of the expression.

3 0

3 years ago

a school netball team won ten matches , lost four and drew 1/8 of the total played . how many matches were drawn and what fracti

defon

The school net ball team drew 2 matches. The team won $\frac{5}{8}$ of total matches played

<h3><u>Solution:</u></h3>

Given, A school netball team won ten matches, lost four and drew $\frac{1}{8}$ of the total played

Let the total number of matches played be "n"

Number of matches drawn = $\frac{1}{8}$ of n

<em>Total matches played = number of won matches + number of lost matches + number of drawn matches</em>

$\begin{array}{l}{n=10+4+\frac{1}{8} n} \\\\ {n-\frac{1}{8} n=10+4}\end{array}$

Taking "n" as common from left hand side,

$\begin{array}{l}{\mathrm{n}\left(1-\frac{1}{8}\right)=14} \\\\ {\mathrm{n} \times \frac{8-1}{8} \quad 14} \\\\ {\mathrm{n} \times \frac{7}{8}=14} \\\\ {\mathrm{n}=16}\end{array}$

So, they played 16 matches in total

Number of matches drawn = $\frac{1}{8}$ of n = $\frac{1}{8} \times 16 = 2$ $\text { Fraction of won matches }=\frac{\text { number of matches won }}{\text { number of matches played }}=\frac{10}{16}=\frac{5}{8}$