If an object is projected upward with an initial velocity of 129129 ft per sec, its height h after t seconds is h equals negati

Question

goblinko [34]

4 years ago

14

If an object is projected upward with an initial velocity of 129129 ft per sec, its height h after t seconds is h equals negati

ve 16 t squared plus 129 th=−16t2+129t. Find the height of the object after 44 seconds.

Mathematics

1 answer:

iragen [17] · Answer 1 · 2021-12-28T00:46:27+03:00

Answer:

260 feet.

Step-by-step explanation:

We have been given that an object is projected upward with an initial velocity of 129 ft per sec, its height h after t seconds is $h(t)=-16t^2+129t$ .

To find the height of object after 4 seconds, we will substitute t=4 in our given function.

$h(4)=-16*4^2+129*4$

$h(4)=-256+516$

$h(4)=260$

Therefore, the height of the object after 4 seconds will be 260 feet.

If an object is projected upward with an initial velocity of 129129 ft per​ sec, its height h after t seconds is h equals negati

If an object is projected upward with an initial velocity of 129129 ft per sec, its height h after t seconds is h equals negati