H(t)=(t+3)^2+5
1 answer:
Answer:
Option C. −4≤t≤−3
Step-by-step explanation:
we have
This is the equation of a vertical parabola written in vertex form
The parabola open upward (the leading coefficient is positive)
The vertex is a minimum
The vertex is the point (-3,5)
The function is increasing in the interval [-3,∞)
The function is decreasing in the interval (-∞,-3]
The function will have a negative average rate when the function will be decreasing
therefore
the answer is option C
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Answer:
4
Step-by-step explanation:
Slope refers to the steepness of the line.
Slope is equal to change in value of y divided by change in value of x.
The slope of the secant line is given by .
Given points are
So, slope of the secant line is
(i) At x = 4.9,
(ii) At x = 4.99,
(iii) At x = 4.999,
(iv) At x = 4.9999,
(v) At x =5.1,
(vi)
At x = 5.01,
(vii) At x = 5.001,
(viii) At x = 5.0001,
(b)
Slope of the tangent line is 4.
Answer: p(-2)=9
Step-by-step explanation:
