H(t)=(t+3)^2+5
1 answer:
Answer:
Option C. −4≤t≤−3
Step-by-step explanation:
we have
This is the equation of a vertical parabola written in vertex form
The parabola open upward (the leading coefficient is positive)
The vertex is a minimum
The vertex is the point (-3,5)
The function is increasing in the interval [-3,∞)
The function is decreasing in the interval (-∞,-3]
The function will have a negative average rate when the function will be decreasing
therefore
the answer is option C
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Answer: a) degree and sign
b) end behavior: left side → +∞, right side → -∞
c) x-intercepts: x = -1.3, 0.3, 1.0
<u>Step-by-step explanation:</u>
end behavior can be determined by two things:
1) the degree of the polynomial:
- if the degree is an even number, then the end behavior will be the same for both the left and right sides.
- if the degree is an odd number, then the end behavior will be different for both the left and right sides.
2) the sign of the leading coefficient:
- If the leading coefficient is positive, then the end behavior of the right side goes to positive infinity
- If the leading coefficient is negative, then the end behavior of the right side goes to negative infinity
W(x) = -5x³ + 7x - 2
Degree: 3 (odd)
Leading Coefficient: negative
So, end behavior is: right side goes to negative infinity, right side goes to positive infinity.
See attachment for x-intercepts. <em>I set the x-axis to represent tenths </em>
Answer:
Step-by-step explanation:
Given
-- Midpoint
Required
Find B
This question will be solved using midpoint formula;
Where
Substitute these values in the midpoint formula;
By comparison; we have:
-- (1)
-- (2)
Solving (1)
Multiply both sides by 2
Subtract 4 from both sides
Solving (2)
Multiply both sides by 2
Subtract 8 from both sides
Hence: