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Liula [17]
3 years ago
13

How many 6-digit numbers can be created using8, 0, 1, 3, 7, and 5 if each number is used only once?

Mathematics
1 answer:
Ludmilka [50]3 years ago
6 0

Answer:

600 numbers

Step-by-step explanation:

For six-digit numbers, we need to use all digits 8,0,1,3,7,5 each once.

However, 0 cannot be used as the first digit, because it would make a 5-digit number.

Therefore

there are 5 choices for the first digit (exclude 0)

there are 5 choices for the first digit (include 0)

there are 4 choices for the first digit

there are 3 choices for the first digit

there are 2 choices for the first digit

there are 1 choices for the first digit

for a total of 5*5*4*3*2*1 = 600 numbers

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Kay has 28 coins which includes nickels and dimes if the total is 2.35$, how many of each coin does Kay have?
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Step-by-step explanation:

Model the situation using two equations, then solve the system.

let n be number of nickels and d be number of dimes.

n + d = 28     <= This equation is about the number of coins.

0.05n + 0.10d =  2.35   <=This equation is about the worth in dollars.

Rearrange n + d = 28.

n = 28 - d

Now we can substitute this equation into the other one.

Sub n =28-d at the "d" variable for the equation 0.05n + 0.10d =  2.35

0.05n + 0.10d =  2.35

Now there is only one variable.

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0.05(28 - d) + 0.10d =  2.35

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Choose the equation n + d = 28 because the numbers are easier.

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