Someone pls help me!!

Mathematics

1 answer:

steposvetlana [31]3 years ago

5 0

Answer:

$r = \frac{12\sin 20\degree}{ \sin 35\degree }$

Step-by-step explanation:

By sine rule

$\frac{r}{ \sin \angle R } = \frac{p}{ \sin \angle P} \\ \\ \frac{r}{ \sin 20\degree } = \frac{12}{ \sin 35\degree } \\ \\ r = \frac{12\sin 20\degree}{ \sin 35\degree }$

You might be interested in

Can someone explain how I'm supposed to determine whether each pair of ratios form a proportion? I so stuck on it sorry can i ge

Natalka [10]

Step-by-step explanation:

We will learn how to solve proportion problems. We know, the first term (1st) and the fourth term (4th) of a proportion are called extreme terms or extremes, and the second term (2nd) and the third term (3rd) are called middle terms or means.

Therefore, in a proportion, product of extremes = product of middle terms

example

1. Check whether the two ratios form a proportion or not:

(i) 6 : 8 and 12 : 16; (ii) 24 : 28 and 36 : 48

Solution:

(i) 6 : 8 and 12 : 16

6 : 8 = 6/8 = 3/4

12 : 16 = 12/16 = 3/4

Thus, the ratios 6 : 8 and 12 : 16 are equal.

Therefore, they form a proportion.

5 0

3 years ago

What are the solutions to the equation (2x – 5)(3x – 1) = 0?

user100 [1]

Answer: $x=\frac{5}{2}, x=\frac{1}{3}$

Explanation:

The equation is:

$(2x-5)(3x-1)=0$

The term on the left consists of a product of two different factors: therefore, this product can be zero if either the first term (2x-5) or the second term (3x-1) is equal to zero.

This means that we can solve separately for the two terms:

$2x-5=0\\3x-1=0$