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3 years ago

I DON'T UNDERSTAND THIS SOMEONE HELP!!

Mathematics

1 answer:

trasher [3.6K]3 years ago

6 0

You're looking for common multiples.
4: 4, 8, 12, 16, 20, 24, ...
6: 6, 12, 18, 24, ...
Since he is on the same machines today, he will be on the same machines again in 12 days.

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Please help me, I don’t know how to solve for x on this one

Brums [2.3K]

Use trigonometry to solve for x.

The tangent function is defined to be opposite side divided by the adjacent side.

tan(78) = x/10

tan(78)(10) = x

47.0463010948 = x

We now round off to two decimal places. In other words, we round off to the nearest tenths.

47.05 = x

Done!

5 0

3 years ago

How do you find the value of c that satisfy the equation:

victus00 [196]

Answer:

The value of c = -0.5∈ (-1,0)

Step-by-step explanation:

Step(i):-

Given function f(x) = 4x² +4x -3 on the interval [-1 ,0]

Mean Value theorem

Let 'f' be continuous on [a ,b] and differentiable on (a ,b). The there exists a Point 'c' in (a ,b) such that

$f^{l} (c) = \frac{f(b) -f(a)}{b-a}$

Step(ii):-

Given f(x) = 4x² +4x -3 …(i)

Differentiating equation (i) with respective to 'x'

f¹(x) = 4(2x) +4(1) = 8x+4

Step(iii):-

By using mean value theorem

$f^{l} (c) = \frac{f(0) -f(-1)}{0-(-1)}$

$8c+4 = \frac{-3-(4(-1)^2+4(-1)-3)}{0-(-1)}$

8c+4 = -3-(-3)

8c+4 = 0

8c = -4

$c = \frac{-4}{8} = \frac{-1}{2} = -0.5$

c ∈ (-1,0)

Conclusion:-

The value of c = -0.5∈ (-1,0)

8 0

3 years ago

Plz help me with this

AnnZ [28]

Answer: $\bold{A)\quad y=5sin\bigg(\dfrac{6}{5}x-\pi\bigg)-4}$

Step-by-step explanation:

The general form of a sin/cos function is: y = A sin/cos (Bx-C) + D where the period (P) = 2π ÷ B

In the given function, $B=\dfrac{6}{5}$ → $P=2\pi \cdot \dfrac{5}{6}=\dfrac{10\pi}{3}$

Half of that period is: $\dfrac{1}{2}\cdot \dfrac{10\pi}{3}=\large\boxed{\dfrac{5\pi}{3}}$

Calculate the period for each of the options to find a match:

$A)\quad B=\dfrac{6}{5}:\quad 2\pi \div \dfrac{6}{5}=2\pi \cdot \dfrac{5}{6}=\dfrac{5\pi}{3}\quad \leftarrow\text{THIS WORKS!}\\\\\\B)\quad B=\dfrac{6}{10}:\quad 2\pi \div \dfrac{6}{10}=2\pi \cdot \dfrac{10}{6}=\dfrac{10\pi}{3}\\\\\\C)\quad B=\dfrac{5}{6}:\quad 2\pi \div \dfrac{5}{6}=2\pi \cdot \dfrac{6}{5}=\dfrac{12\pi}{5}\\\\\\D)\quad B=\dfrac{3}{10}:\quad 2\pi \div \dfrac{3}{10}=2\pi \cdot \dfrac{10}{3}=\dfrac{20\pi}{3}$

7 0

3 years ago

State the value of the discriminant of -6x^2 +2x + 3 = 0

Dmitry [639]

Answer:

Step-by-step explanation:

recall that for a quadratic equation in the form

ax² + bx + c = 0, the discriminant is given by

discriminant, D = b²- 4ac

we are given the following:

-6x² + 2x + 3 = 0,

comparing this with the general equation above, it is clear that,

a = -6, b = 2 and c = 3,

substituting these into our equation for discriminant:

D = b²- 4ac

= 2² - 4(-6)(3)

= 4 + 72

= 76

4 0

3 years ago

Please help no troll im really confused i'm offering 20 points

MatroZZZ [7]

Answer:

4) choice 1) 14.7 cm

5) choice 2) 14.8 cm

Step-by-step explanation:

4) 10^2 + 10^2 + 4^2 = 216

sq rt 216 = 14.7

5) 14^2 + 3^2 + 4^2 = 221

sq rt 221 = 14.86

3 0

3 years ago