All categories

2 years ago

To make a certain shade of paint, Anya mixed 2/3

Mathematics

1 answer:

Jlenok [28]2 years ago

4 0

Answer:

4 cups

Step-by-step explanation:

it should be 4 cups

You might be interested in

Leanne runs on the treadmill and rides the exercise bike at the gym to stay in shape. She burns 15 calories per minute on the tr

sergiy2304 [10]

Answer: C.

Explanation: i just took it. and got a 100. :)

8 0

2 years ago

The highest common factor of 18, 24, 36 is

yawa3891 [41]

If you list all the common factors, (1,2,3,6), you see the highest common factor is 6

6 0

3 years ago

Read 2 more answers

1. y = x2 + 2x – 8 Axis of Symmetry: Vertex: Domain: Range:

valentinak56 [21]

Answer:

Axis of Symmetry: x=-1

Vertex: (-1,-9)

Domain: (- ∞ ,∞ )

Range: (-9,∞ )

Step-by-step explanation:

6 0

3 years ago

3. A technician worked 45 hours in one week He gets paid double for every hour over 40 hours that he works. If his regular wage

8090 [49]

Answer: 41,250$ (I think)

Step-by-step explanation:

1 hour —> 825$

40 hours —> 825$ x 40 = 33,000$

The after the 40 hours he gets paid x2 and he works for 5 hours

1 hour —> 825$ x 2 = 1,650$

5 hours —> 1650$ x 5 = 8,250$

33,000 + 8,250 = 41,250$

6 0

3 years ago

A 15-ft ladder rests against a vertical wall. If the top of the ladder slides down the wall at a rate of 0.33 ft/sec, how fast,

3241004551 [841]

Answer:

0.44 ft/sec.

Step-by-step explanation:

Let A is the bottom of the ladder and AB is the distance from the bottom of the wall i.e. B is the bottom of the wall. If C is the top of the ladder and BC is the height of the wall.

Now, Δ ABC is a right triangle and AC is the length of the ladder i.e. hypotenuse.

Now, AC² = AB² + BC² {From Pythagoras Theorem}

Now, differentiating both sides with respect to time t, we get

$0 = 2 \times (AB) \times \frac{d(AB)}{dt} + 2 \times (BC) \times \frac{d(BC)}{dt}$

⇒ $\frac{d(AB)}{dt} = - \frac{BC}{AB} \times \frac{d(BC)}{dt}$

Now, given that $\frac{d(BC)}{dt} = - 0.33$ feet/sec.

Hence, $\frac{d(AB)}{dt} = - \frac{BC}{AB} \times (- 0.33)$ ......... (1)

Now, given that AB = 9 ft. and AC = 15 ft.

So, 15² = 9² + BC²

⇒ BC² = 144

⇒ BC = 12 feet.

Now, from equation (1), we get

$\frac{d(AB)}{dt} = - \frac{12}{9} \times (- 0.33) = 0.44$

Therefore, the bottom of the ladder is sliding away from the wall at the rate of 0.44 ft/sec. (Answer)

3 0

3 years ago