D = 20
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∫¹₀ min (1, n/y)dy = ∫ⁿ₀ (1, n/y)dn + ∫¹n min (1, n/y) dy
Hope this helps
Answer:
A. -4
Step-by-step explanation:
Given the function f(x) = x + 3 for x ≤ -1 and 2x - c for x > -1, for the function to be continuous, the right hand limit of the function must be equal to its left hand limit.
For the left hand limit;
The function at the left hand occurs at x<-1
f-(x) = x+3
f-(-1) = -1+3
f-(-1) = 2
For the right hand limit, the function occurs at x>-1
f+(x) = 2x-c
f+(-1) = 2(-1)-c
f+(-1) = -2-c
For the function f(x) to be continuous on the entire real line at x = -1, then
f-(-1) = f+(-1)
On equating both sides:
2 = -2-c
Add 2 to both sides
2+2 = -2-c+2
4 =-c
Multiply both sides by minus.
-(-c) = -4
c = -4
Hence the value of c so that f(x) is continuous on the entire real line is -4
Answer:
Solution of the equation 4x + 5 = 3x + 4 is:
x= -1
Step-by-step explanation:
We are given a equation:
4x + 5 = 3x + 4
We have to solve the equation for x
4x+5=3x+4
subtracting both sides by 4
4x+5-4=3x+4-4
4x+1=3x
subtracting both sides by 4x
4x|+1-4x=3x-4x
1= -x
⇒ x= -1
Hence, solution of the equation 4x + 5 = 3x + 4 is:
x= -1
