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katrin [286]
3 years ago
8

In the fraction 5_8what is the term used to designate the 5

Mathematics
1 answer:
jek_recluse [69]3 years ago
3 0
\frac{Numerator}{Denominator}


In this case the 5 is on top so it is the Numerator
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A college student took 4 courses last semester. His final grades, along with the credits each class is worth, are as follow: A (
NikAS [45]

Answer:

A college student took 4 courses last semester. His final grades, along with the credits each class is worth, are as follow: A (3), B (4), C (2), and D (3). The grading system assigns quality points as follows: A: 4; B: 3; C: 2; D: 1; and F: 0. Find the student’s GPA for this semester. Round your answer to the nearest thousandth.

another way is

This is a weighted average question. You are going to "weight" each course by the number of credits it is worth and then divide by the total number of credits. In other words, you are going to multiply each grade (A=4, B=3) by the number of credits attached to that grade. This will ensure that the courses that have more credits count more in the overall average. Then you are going to divide by the total number of credits to get the overall GPA.

So,

(3*4 + 4*3 + 2 *2 + 3*1)/(3+4+2+3) = GPA

Step-by-step explanation:

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6 0
3 years ago
Find the area if the figure using 3.14
Veronika [31]
The area of the square is 9, the area of all the semi circles added together is 15.7, when you add them together you get 24.7
8 0
3 years ago
Help me please.....​
PolarNik [594]

Answer: I believe its Option 2

Step-by-step explanation: Sory if im wrong

8 0
2 years ago
Read 2 more answers
What is the sum of 15 – 6i and –2 + 9i? 13 + 3i 17 + 3i 24 – 147i 24 + 147i
Delicious77 [7]

13 + 3i

15 - 6i - 2 + 9i  → Sum

collect like terms

(15 - 2) + ( - 6i + 9i) =13 + 3i


7 0
3 years ago
Read 2 more answers
Reflect quadrilateral CJKM across the y-axis. Find the location of K'.
Montano1993 [528]

K(1,4)\rightarrow K^{\prime}(-1,4)

Explanation

Step 1

find the coordinate of every point of the quadrilateral

C(-3,1)

J(0,1)

K(1,4)

M(4,-2)

Step 2

When you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate is transformed into its opposite (its sign is changed).

so

(x,y)\rightarrow reflect\text{ across y -Ax is}\rightarrow(-x,y)

therefore

\begin{gathered} C\mleft(-3,1\mright)\rightarrow C^{\prime}(3,1) \\ J\mleft(0,1\mright)\rightarrow J^{\prime}(0,1) \\ K\mleft(1,4\mright)\rightarrow K^{\prime}(-1,4) \\ M(4,-2)\rightarrow M^{\prime}(-4,-2) \end{gathered}

so, the answer is

K^{\prime}(-1,4)

i hope this helps you

4 0
1 year ago
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