Rectangle is 2/5 in. long and 1/3 in. wide.
1 answer:
Answer: "<span>
in²</span> " . {that is: " (2/15) in² . "}.
___________________________________________
Explanation:
___________________________________________
The formula/equation for the Area of a rectangle:
A = L * w ;
in which: L = <span>⅖ in ;
</span> w = ⅓ in;
___________________________
Find the area; in a "fraction value" ;
_______________________________
A = L * w ;
→ Substitute the given values for "L" (length) and "w" (width);
and solve for "A" (area) in the "form of a fraction:
__________________________________________________
A = (2/15) in * (1/3) in ;
→ A = [(2*1) / (5*3)] * in * in ;
______________________________________________________
→ Answer: The area is: " in² " .
{that is, "(2/15) in² " .}.
______________________________________________________
___________________________________________
Explanation:
___________________________________________
The formula/equation for the Area of a rectangle:
A = L * w ;
in which: L = <span>⅖ in ;
</span> w = ⅓ in;
___________________________
Find the area; in a "fraction value" ;
_______________________________
A = L * w ;
→ Substitute the given values for "L" (length) and "w" (width);
and solve for "A" (area) in the "form of a fraction:
__________________________________________________
A = (2/15) in * (1/3) in ;
→ A = [(2*1) / (5*3)] * in * in ;
______________________________________________________
→ Answer: The area is: "
{that is, "(2/15) in² " .}.
______________________________________________________
You might be interested in
Answer:
Graph = Cardioid
Axis of symmetry = y-axis
Critical points=
Step-by-step explanation:
General equation for this type of cardioid is:
a ± b sinθ
Condition for a cardioid =
Axis of symmerty according to the graph of 2 + 2 sinθ is along y-axis.
Critical points:
r = 2 + 2 sinθ ⇒ r = 2(1 + sinθ) ⇒ r' = 2 cosθ
∵derivative of 1 + sinθ = cosθ
For finding critical point the derivative is equal to zero,
2 cosθ = 0 ⇒ cosθ = 0
the value of cosθ is equal to zero at intervals:
So, critical points =
