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user100 [1]
4 years ago
15

A certain isotope decays so that the amount A remaining after t years is given by:

Mathematics
1 answer:
pashok25 [27]4 years ago
3 0

f(h(x))= 2x -21

Step-by-step explanation:

f(x)= x^3 - 6

h(x)=\sqrt[3]{2x-15}

WE need to find f(h(x)), use composition of functions

Plug in h(x)

f(h(x))=f(\sqrt[3]{2x-15})

Now we plug in f(x) in f(x)

f(h(x))=f(\sqrt[3]{2x-15})=(\sqrt[3]{2x-15})^3 - 6

cube and cube root will get cancelled

f(h(x))= 2x-15 -6= 2 x-21

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Someone help plzzz!!! This is due today before 11pm
monitta

Answer:

1470.24 in^3

Step-by-step explanation:

Square: 12*6*11=792

Circle: 6*(3.14*6^2)=678.24

792+678.24=1470.24

6 0
3 years ago
What is<br> 51=3x<br> Please help me
damaskus [11]

Answer:

17 = x

Step-by-step explanation:

51 = 3x

~Divide 3 to both sides

17 = x

Best of Luck!

3 0
3 years ago
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How fast did lsabella fill her pool?
MissTica
More information please
7 0
3 years ago
Complete the following table for residuals for the exponential function: f(x) = 49.3(1.47)
agasfer [191]

Answer:

Predicted values:

\hat y_1 = 49.3 (1.47)^1 =72.471

\hat y_2 = 49.3 (1.47)^2 =106.5324

\hat y_3 = 49.3 (1.47)^3 =156.6026

\hat y_4 = 49.3 (1.47)^4 =230.2058

\hat y_5 = 49.3 (1.47)^5 =338.4025

\hat y_6 = 49.3 (1.47)^6 =497.4517

\hat y_7 = 49.3 (1.47)^7 =731.254

\hat y_8 = 49.3 (1.47)^8 =1074.943

Residuals:

e_1 = 65-72.471=-7.471

e_2 = 90-106.5324=-16.5324

e_3 = 162-156.6026 = 5.3974

e_4 = 224-230.2058 = -6.2058

e_5 = 337-338.4025 = -1.4025

e_6 = 466-497.4617 = -31.4517

e_7 = 780-731.254 = 48.7459

e_8 = 1087-1074.493 = 12.0566

Step-by-step explanation:

For this case we assume the following exponential function:

\hat y_i = 49.3 (1.47)^x

Where x represent the hours and y the predicted values for each hour. We can find the estimated values like this:

\hat y_1 = 49.3 (1.47)^1 =72.471

\hat y_2 = 49.3 (1.47)^2 =106.5324

\hat y_3 = 49.3 (1.47)^3 =156.6026

\hat y_4 = 49.3 (1.47)^4 =230.2058

\hat y_5 = 49.3 (1.47)^5 =338.4025

\hat y_6 = 49.3 (1.47)^6 =497.4517

\hat y_7 = 49.3 (1.47)^7 =731.254

\hat y_8 = 49.3 (1.47)^8 =1074.943

Now we can find the residuals with this formula:

e_i = Y_i -\hat y_i

And replacing we got:

e_1 = 65-72.471=-7.471

e_2 = 90-106.5324=-16.5324

e_3 = 162-156.6026 = 5.3974

e_4 = 224-230.2058 = -6.2058

e_5 = 337-338.4025 = -1.4025

e_6 = 466-497.4617 = -31.4517

e_7 = 780-731.254 = 48.7459

e_8 = 1087-1074.493 = 12.0566

6 0
3 years ago
To prove ∆LMN ≅ ∆PQR by SSS you need _______________ and<br> ______________ and ______________
Elis [28]

Given:

To prove ∆LMN ≅ ∆PQR by SSS you need _____________ and

_______________ and ______________.

To find:

The missing values.

Solution:

If ∆LMN ≅ ∆PQR by SSS, then all sides of ∆LMN are congruent to corresponding sides of ∆PQR.

LM\cong PQ

MN\cong QR

LN\cong PR

Therefore, the missing values are LM\cong PQ, MN\cong QR,LN\cong PR.

6 0
4 years ago
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