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3 years ago

A certain isotope decays so that the amount A remaining after t years is given by:

Mathematics

1 answer:

pashok25 [27]3 years ago

3 0

f(h(x))= 2x -21

Step-by-step explanation:

f(x)= x^3 - 6

h(x)=\sqrt[3]{2x-15}

WE need to find f(h(x)), use composition of functions

Plug in h(x)

f(h(x))=f(\sqrt[3]{2x-15})

Now we plug in f(x) in f(x)

f(h(x))=f(\sqrt[3]{2x-15})=(\sqrt[3]{2x-15})^3 - 6

cube and cube root will get cancelled

f(h(x))= 2x-15 -6= 2 x-21

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3 years ago

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Sin^2(x/2)=sin^2x <br> Find the value of x

Veronika [31]

$\sin^2\dfrac x2=\sin^2x$
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3 years ago

Solve for x.<br> y=x-6<br> y=9<br> Simplify your answer as much as p

lukranit [14]

Step-by-step explanation:

$y + 6 = x \\ y = 9 \\ x = 9 + 6 \\ x = 15$

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3 years ago

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poizon [28]

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3 years ago

Express the following vector in the form v=v1i+v2j+v3k. 3u - v if u=(4,7,-3) and v=(2,-7,5).3u - v = ____ i + ____ j + _____ k.(

Alecsey [184]

Answer:

Step-by-step explanation:

Given the vectors u = (4,7,-3) and v=(2,-7,5), both vectors are 3-dimensional in nature and can also be rewritten as;

u = 4i+7j-3k and v = 2i-7j+5k

To get 3u-v, we will substitute the given vectors into the expression;

3u-v = 3(4i+7j-3k) - (2i-7j+5k)

open the parenthesis

3u-v = 12i+21j-9k - 2i + 7j - 5k

collect like terms

3u-v = (12i - 2i) + (21j + 7j) (-9k-5k)

3u - v = 10i+28j-14k

To simplify the answer, we will divide through by 2

3u - v = 10i/2+28j/2-14k/2

<em>Hence the simplified form of the expression is 5i+14j-7k</em>

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3 years ago