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3 years ago

In the ordered pair (3, 4), which number represents the x-coordinate

Mathematics

1 answer:

zavuch27 [327]3 years ago

3 0

Answer:

Step-by-step explanation:

Coordinate pairs are represented like this (x, y). So since 3 is in the first spot, it is the x coordinate.

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A convenience store purchased a magazine and marked it up 100% from the original cost of $2.30. A week later, the store placed t

77julia77 [94]

Answer:

$2.30

Step-by-step explanation:

The original price is $2.30 an it goes up by 100% which means another 2.30. So add 2.30 and 2.30 together you get 4.60 now divide that by two since the magazine is 50% off and you get the original price which was 2.30

5 0

3 years ago

Read 2 more answers

Find the equation of the line of symmetry of y= (x+2)(x-8).

Daniel [21]

Answer:

line of symmetry , x = 3

Step-by-step explanation:

Standard form of quadratic equation is y = ax^2 + bx + c, where a, b, and c equal all real numbers. You can use the formula x = -b / 2a to find the line of symmetry.

$y = (x+ 2)(x-8)\\\\y = (x^2 -8x + 2x -16)\\\\y = x^2 -6x -16$

a = 1, b = -6, c = -16

Line of symmetry is ,

$x = -\frac{b}{2a} = -\frac{-6}{2} = 3$

4 0

3 years ago

Find all the zeros of the equation x^4-6x^2-7x-6=0

rusak2 [61]

Answer:

The zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Step-by-step explanation:

We have been given the equation x^4-6x^2-7x-6=0

Use rational root theorem, we have

$a_0=6,\:\quad a_n=1$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:3,\:6,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:3,\:6}{1}$

$-\frac{2}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+2$

$=\left(x+2\right)\frac{x^4-6x^2-7x-6}{x+2}\\$

$=x^3-2x^2-2x-3$

Again factor using the rational root test, we get

$=\left(x+2\right)\left(x-3\right)\left(x^2+x+1\right)$

Using the zero product rule, we have

$x+2=0:\quad x=-2\\x-3=0:\quad x=3\\x^2+x+1=0\\\\x_{1,\:2}=\frac{-1\pm \sqrt{1^2-4\cdot \:1\cdot \:1}}{2\cdot \:1}\\\\=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Therefore, the zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

4 0

3 years ago

Read 2 more answers

- 7 ( x - 2 ) + 1 = 15 - 7x

Savatey [412]

Answer: x=1

Step-by-step explanation:

You need to open up the parenthesis so you multiply every term inside the parenthesis by -7.

1. -7x + 14 + 1 = 15 -7x

2. Combine like terms -7x + 15 = 15-7x

The two sides of the equation are the same so that means that x=1

5 0

3 years ago

Determine the length of the unknown sides for the right triangle

alisha [4.7K]

Answer:

Below in bold.

Step-by-step explanation:

sin 66.4 = opposite side / hypotenuse

sin 66.4 = 21.3 / y

y = 21.3 / sin 66.4

y = 23.24.

tan 66.4 = 21.3 / x

x = 21.3 / tan 66.4

x = 9.31.

3 0

3 years ago