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3 years ago

Solve for x in 2^3x+1= 5^x+1

Mathematics

2 answers:

Solnce55 [7]3 years ago

6 0

Answer:

x=0

Step-by-step explanation:

Inessa05 [86]3 years ago

6 0

Answer:

1.949539695

Step-by-step explanation:

2^3x+1=5^x+1

(2^3x)*(2^1)= (5^x)*(5^1)

((2^3)^x)/(5^x)=5/2

(8^x)/(5^x)=2.5

(8/5)^x=2.5

log1.6(2.5)=x

x=1.949539695

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gregori [183]

Answer:

Step-by-step explanation:

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2 years ago

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ludmilkaskok [199]

Answer:

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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3 years ago

H(x) = x2 1 k(x) = x – 2 (h k)(2) = (h – k)(3) = Evaluate 3h(2) 2k(3) =.

natima [27]

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.The value of the given functions are,

$(h+k)(x)=5$

$(h-k)(x)=9$

$3h(2)+2k(3)=17$

<h3>Given information-</h3>

The given function is,

$h(x)=x^2+1$

$k(x)=x-2$

<h3>Quadratic equation</h3>

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.

1) The value of the function (h+k)(2),

$(h+k)(x)=h(x)+k(x)$

$(h+k)(x)=x^2+1+x-2$

$(h+k)(2)=2^2+1+2-2$

$(h+k)(x)=5$

2)The value of the function (h-k)(3),

$(h-k)(x)=h(x)-k(x)$

$(h-k)(x)=x^2+1-x+2$

$(h-k)(3)=3^2+1-3+2$

$(h-k)(x)=9$

3) The value of the function 3h(2)+2k(3)

$3h(x)+2k(x)=3x^2+3+2x-2\times 2$

$3h(2)+2k(3)=3\times2^2+3+2\times2-2\times 2$

$3h(2)+2k(3)=17$

Hence the value of the given functions are,

$(h+k)(x)=5$

$(h-k)(x)=9$

$3h(2)+2k(3)=17$

Learn more about the quadratic equation here;

brainly.com/question/2263981

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2 years ago

Solve for x in 2^3x+1= 5^x+1​

Solve for x in 2^3x+1= 5^x+1