
factorising the first denominator
x²-2x-3 = x² -3x+x-3 = (x+1)(x-3)
(a) 
finding LCD
(b) LCD of (x-3)(x+1) and (x-3) is (x-3)(x+1)
(c)

(d)



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Answer:
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Answer:

Step-by-step explanation:
Since we are not given a midpoint, we use the Angle Addition Postulate:
156 = [x + 109] + [x + 53]
156 = 162 + 2x
-162 - 162
_______________
−6 = 2x
___ ___
2 2
−3 = x
[−3 + 53] + [−3 + 109] = 156
50 106
156 = 156 ☑
Therefore,
is a genuine statement.
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