9514 1404 393
Answer:
3.61 seconds
Step-by-step explanation:
The bird starts 50 feet in the air, so will come down to a height of 40 feet after 3.61 seconds.
We want to solve h = 40.
40 = -16t^2 +55t +50
16t^2 -55t -10 = 0
t = (55 +√(55^2 -4(16)(-10)))/(2(16)) = (55 + √3665)/32 ≈ 3.61060
The bird will be 40 ft above the ground the first time after about 3.61 seconds.
The two long sides are 63meters and the shorter sides are 21meters.
Answer:
5 seconds
Step-by-step explanation:
Looking at your function (h(t) = -16t^2 + 48t + 160), I see that the peak height will be 196 feet, and that is achieved in 1.5 seconds.
h(1.5) = -16(1.5)^2 + 48(1.5) + 160
h(1.5) = -16(2.25)+ 48(1.5) + 160
h(1.5) = -36 + 48(1.5) + 160
h(1.5) = -36 + 72 + 160
h(1.5) = 36 + 160
h(1.5) = 196
Going down from that height, it would take 3.5 more seconds, so it would take 5 seconds in total
h(5) = -16(5)^2 + 48(5) + 160
h(5) = -16(25) + 48(5) + 160
h(5) = -400 + 48(5) + 160
h(5) = -400 + 240 + 160
h(5) = -400 + 400
h(5) = 0
Answer:
x= 1/3 =0.333
Step-by-step explanation:
