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I am Lyosha [343]
3 years ago
13

A 66.5kg astronaut is doing a repair in space on the orbiting space station. She throws a 2.30kg tool away from her at 3.10m/s r

elative to the space station
A) With what speed will she begin to move?
B) In what direction will she begin to move?
A) Opposite to the direction in which she throws the tool
B) To the direction in which she throws the tool
Physics
1 answer:
MrRa [10]3 years ago
6 0

Answer:

Explanation:

mass of astronaut, M = 66.5 kg

mass of tool, m = 2.3 kg

velocity of tool, v = 3.10 m/s

Let the velocity of astronaut is V.

(A) According to the conservation of moemntum

Momentum of astronaut = Momentum of tool

M x V = m x v

66.5 x V = 2.3 x 3.10

V = 0.107 m/s

(B) The direction of motion of astronaut is opposite to the direction of motion of tool.

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<u>Answer:</u> The number of electrons in given amount of silver are 1.87\times 10^{24}

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

We are given:

Given mass of silver = 7.1 g

Molar mass of silver = 107.87 g/mol

Putting values in above equation, we get:

\text{Moles of silver}=\frac{7.1g}{107.87g/mol}=0.066mol

Number of electrons in 1 atom of silver = 47

According to mole concept:

1 mole of an element contains 6.022\times 10^{23} number of particles

So, 0.066 moles of silver will contain = -(0.066\times 47\times 6.022\times 10^{23})=1.87\times 10^{24} number of electrons

Hence, the number of electrons in given amount of silver are 1.87\times 10^{24}

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A shopping cart given an initial velocity of 2.0 m/s north undergoes a constant acceleration of 3.0 m/s2 north. what is the dist
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Following the initial 4.0 seconds of travel, the cart moved 32m.

<h3>What is an equation of motion?</h3>

Physicists use equations of motion to describe how a physical system behaves in terms of how its motion changes over time.

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7 0
2 years ago
An experiment is conducted on a long straight wire of diameter d. A constant current is sent through the wire and the magnetic f
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Answer:

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Explanation:

To solve the exercise it is necessary to apply the concepts related to the Magnetic Field described by Faraday.

The magnetic field is given by the equation:

B = \frac{\mu_0 I}{2\pi d}

Where,

\mu = Permeability constant

d = diameter

I = Current

For the given problem we have a change in the diameter, twice that of the initial experiment, therefore we define that:

B_1 = \frac{\mu_0 I}{2\pi d}

B_2 = \frac{\mu_0 I}{2\pi 2d}

The ratio of change between the two is given by:

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\frac{B_2}{B_1} = \frac{d}{2d}

\frac{B_2}{B_1} = \frac{1}{2}

B_2 = B_1 \frac{1}{2}

Therefore the correct answer is D.

4 0
3 years ago
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