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Luda [366]
3 years ago
14

Help me please thanks

Mathematics
1 answer:
balu736 [363]3 years ago
6 0

Answer:

x < (with the line at the bottom) -2. So the third answer choice.


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a bookstore has four boxes of books each box contains 20 books on Monday the book store sold 16 books how many books remain to b
vitfil [10]

Answer:64

Step-by-step explanation:

You have the other 3 box's with 20 left which is 60 so all you gotta do is 20-16 which is 4

6 0
3 years ago
4{2a(3a-b)+3ab}+5{3b(a+2b)-4ab}
Paraphin [41]
Follow order of operations.
Distribute what is in the parentheses.
4[6a^2 -2ab +3ab] + 5[3ab + 6b^2 -4ab]

Combine like terms in the brackets.
4[6a^2 + 3ab] + 5[-1ab + 6b^2]

Distribute the 4 and the 5.
24a^2 + 12ab -5ab + 30b^2

Combine like terms.
24a^2 +7ab + 30b^2

That's your final answer:
24a^2 +7ab + 30b^2
5 0
3 years ago
Quadrilateral JKLM is graphed with vertices at J(-2,2), K(-1,-5), L(4,0), and M(3,7).
AveGali [126]

Answer:

<u>Question (a)</u>

Midpoint of a line segment:

M=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Given:

  • J = (-2, 2)
  • L = (4, 0)

\implies \textsf{midpoint of }JL=\left(\dfrac{-2+4}{2},\dfrac{2+0}{2}\right)=(1,1)

Given:

  • M = (3, 7)
  • K = (-1, -5)

\implies \textsf{midpoint of }MK=\left(\dfrac{3-1}{2},\dfrac{7-5}{2}\right)=(1, 1)

<u>Question (b)</u>

Find slopes (gradients) of JL and MK then compare.  If the product of the slopes of JL and MK equal -1, then JL and MK are perpendicular.

\textsf{slope }m=\dfrac{y_2-y_1}{x_2-x_1}

Given:

  • J = (-2, 2)
  • L = (4, 0)

\implies \textsf{slope of }JL=\dfrac{0-2}{4+2}=-\dfrac13

Given:

  • M = (3, 7)
  • K = (-1, -5)

\implies \textsf{slope of }MK=\dfrac{-5-7}{-1-3}=3

\textsf{slope of }JL \times \textsf{slope of }MK=-\dfrac13 \times3=-1

Hence segments JL and MK are perpendicular

4 0
2 years ago
Help Please (I needed 20 characters)
liq [111]
Is a (0,18) ? not sure though baha.
4 0
3 years ago
Identify an equation in point-slope form for the line perpendicular to
Alik [6]

Answer:

C

Step-by-step explanation:

Perpendicular lines have the exact opposite slope of the other equation.

So the slope will be x or 1x. Plug in

-8 = 1(4) + b (b represents y-intercept) like y=mx+b

-8 = 4 + b (subtract 4 on both sides)

-12 = b

The equation is y = x - 12

C

solve

y + 8 = x - 4 (subtract 8 on both sides)

y = x - 12

7 0
3 years ago
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