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irinina [24]
3 years ago
13

Assuming a 90% confidence level, the margin of error is approximately?

Mathematics
1 answer:
elena-s [515]3 years ago
7 0

Answer:

  0.3

Step-by-step explanation:

The margin of error is calculated as ...

  (standard deviation)/√(sample size) × (z*-score)

where the z*-score is chosen based on the desired confidence level.

Here, you have ...

  • standard deviation = 2.7
  • √(sample size) = √225 = 15
  • z*-score for 90% confidence level = 1.645

Putting these values in the above expression for margin of error gives ...

  2.7/15·1.645 = 0.2961 ≈ 0.3

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<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

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