Answer:
Let's solve your system by elimination.
3x+4y=29;6x+5y=43
Multiply the first equation by -2,and multiply the second equation by 1.
−2(3x+4y=29)
1(6x+5y=43)
Becomes:
−6x−8y=−58
6x+5y=43
Add these equations to eliminate x:
−3y=−15
Then solve−3y=−15for y:
−3y=−15
−3y
−3
=
−15
−3
(Divide both sides by -3)
y=5
Now that we've found y let's plug it back in to solve for x.
Write down an original equation:
3x+4y=29
Substitute5foryin3x+4y=29:
3x+(4)(5)=29
3x+20=29(Simplify both sides of the equation)
3x+20+−20=29+−20(Add -20 to both sides)
3x=9
3x
3
=
9
3
(Divide both sides by 3)
x=3
Answer:
x=3 and y=5
Step-by-step explanation:
I love this stuff 229 999 0523
You need to make a proportion.
45 X
------ -----
100 480
45 x 408 is 21600 ÷ 100 is 216.
so ur answer is 216
hope that helps
Answer:
a^3 + a^2
Step-by-step explanation:
Distribute the term left of each set of parentheses, then combine like terms.
-a²(3a - 5) + 4a(a² - a) =
= -3a^3 + 5a^2 + 4a^3 - 4a^2
= a^3 + a^2
Answer: x = 2921, y = 579
Step-by-Step Explanation:
I am assuming that we just have to Solve for ‘x’ and ‘y’.
‘x’ = No. Of Contemporary Titles
‘y’ = No. Of Classic Titles
=> x + y = 3500 (Eq. 1)
=> x - y = 2342 (Eq. 2)
Adding Eq. 1 and Eq. 2, we get :-
2x = 3500 + 2342
2x = 5842
x = 5842/2
=> x = 2921
Therefore, x = 2921
Substitute value of ‘x’ in Eq. 1 :-
x + y = 3500
(2921) + y = 3500
y = 3500 - 2921
=> y = 579
Therefore, y = 579
Hence,
No. Of Contemporary Titles = 2921
No. Of Classic Titles = 579
