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creativ13 [48]
3 years ago
10

Given that there is a 20% chance of rain today,what is the probability that they lose their game​

Mathematics
1 answer:
den301095 [7]3 years ago
7 0

Answer:

Either it rains and they lose, which has probability 20% * 20% = 4%.  

Or it doesn't rain and they lose, which has probability 80% * 50% = 40%.  

Adding these two probabilities gives us 44%

Step-by-step explanation:

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Given the proportional steel cost, how much do 200 pounds of steel cost?
kotegsom [21]

Answer:

Your answer is B, 150

Step-by-step explanation:

If we look at the chart it says 160 pounds of steel is 120, so for example if we start from 40 we will have 30, so every time we add 40 pounds 30$ are added, meaning that 160+40=200, 120+30= 150, Thus B or 150 is our answer.

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What is the best measure of center for this data?
brilliants [131]

Answer:

The answer is A

Becaise Mode is not a measure of centre, and Mean is dramatically changed with the outli

I think that would be correct, Hope it helps!!!

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2 years ago
Hey sandwich shop has 80 stores and 60% of the stores are in California the rest of the stores are in Nevada how many stores are
umka2103 [35]

\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{60\% of 80}}{\left( \cfrac{60}{100} \right)80}\implies 48~\hfill \begin{array}{cllll} \stackrel{california}{\underset{60\%}{48}}\\\\ \stackrel{nevada}{\underset{the~rest}{32}} \end{array}

6 0
2 years ago
A rectangular athletic field is twice as long as its wide. If the perimeter of the athletic field is 180 yards, what are the dim
andrezito [222]

Answer:

l = 60 yd; w = 30 yd

Step-by-step explanation:

We have two bits of information

(a) The perimeter of the rectangle

The formula for the perimeter of a rectangle is

             P = 2l + 2w

             P = 180 yd     Insert into the formula

(1) 2l + 2w = 180

===============

(b) The length-to-width ratio

(2) l = 2w

Substitute the value of l from Equation (2) into Equation (1)

2×(2w) + 2w = 180

===============

Solve for w

4w + 2w = 180     Combine like term s

        6w = 180     Divide each side by 6

          w = 30 yd

===============

Solve for l

Substitute the value for w into Equation (1).

2l +2×30 = 180

   2l +60 = 180     Subtract 60 from each side

          2l = 120      Divide each side by 2

            l = 60 yd

The field is 60 yd long and 30 yd wide.

===============

<em>Check</em>:

P = 2×60 + 2×30

P = 120 + 60

P = 180 yd

Also

60 = 2 × 30

60 = 60

6 0
3 years ago
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