The quotient is 6
18/3 = 6
1: AAS 2: SAS 3: AAS 4: SAS 5: not congruent 6: SSS
Answer:
The answer to your question is letter A
Step-by-step explanation:
Polynomial 4x¹⁰ + 9x¹⁰
To sum or subtract polynomials, just look for like terms and do the operations considering the rules of signs.
In this problem both terms are like terms, then we add the coefficients and write the variable without a change.
4x¹⁰ + 9x¹⁰ = 13x¹⁰
Answer:
Height of building is 76 feets
Step-by-step explanation:
The scenario is illustrated in the attached photo. The stretched rope is seen coming from the top of the building, passing through the top of the tree which is halfway the height of the building and touching the state which is on the ground.
The distance, x of the tree to the building on the ground is equal to the distance, x of the tree from the stake, hence,
Distance of the stake from the building is 2x
Height of the tree = 38 feets
Height of the building = y feets
The triangles formed are similar triangles. Therefore,
38/x = y/2x
Cross multiplying
2x × 38 = x × y
xy = 76x
y = 76x/x = 76 feets
Answer:
![\left[\begin{array}{ccc}3&0&0\\0&3&0\\0&0&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%260%260%5C%5C0%263%260%5C%5C0%260%263%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
In order to find out the resulting matrix, we will have to multiply the identity matric and the scalar 3:
The 3x3 identity matrix is:
![\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%260%5C%5C0%261%260%5C%5C0%260%261%5Cend%7Barray%7D%5Cright%5D)
Multiplying with scalar 3:
![3\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]](https://tex.z-dn.net/?f=3%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%260%5C%5C0%261%260%5C%5C0%260%261%5Cend%7Barray%7D%5Cright%5D)
The scalar will be multiplied by each element of the matrix.
Multiplying zeros with scalar 3 will give us zero. So the resulting matrix will be:
![\left[\begin{array}{ccc}3*1&0&0\\0&3*1&0\\0&0&3*1\end{array}\right] = \left[\begin{array}{ccc}3&0&0\\0&3&0\\0&0&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%2A1%260%260%5C%5C0%263%2A1%260%5C%5C0%260%263%2A1%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%260%260%5C%5C0%263%260%5C%5C0%260%263%5Cend%7Barray%7D%5Cright%5D)
So the resultant matrix will be a scalar matrix with 3 at diagonal positions..
