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e-lub [12.9K]
3 years ago
14

there is an antenna on the top of a building. From a location 300 ft from the base of the building, the angle of elevation to th

e top of the building is measured to be 40 degrees. From the same location the angle of elevation to the top of the antenna is measured to be 43 degrees. find the height of the antenna
Mathematics
1 answer:
lukranit [14]3 years ago
7 0

Answer:

300tan43 - 300tan40

Step-by-step explanation:

Use tangent to find the height of the building:

tan40 = b/300

b = 300tan40

The use tangent to find the height to the top of the antenna:

tan43 = a/300

a = 300tan43

The antenna height = a - b

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The bike store marks up the wholesale cost of all of the bikes they sell by 30%.
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Answer:

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B ) The money which Andre pay for the bike is $ 76.92

Step-by-step explanation:

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A ) The discount percentage = 30 %

Let The selling price of the bike after discount = s.p

Now ,

Discount % = \dfrac{m.p - s. p }{m . p}

or, 30 % = 1 - \dfrac{s. p }{m . p}

or, \dfrac{30 }{100} = 1 - \dfrac{s. p }{96.15}

Or, \dfrac{s. p }{96.15} = 1 -  \dfrac{30 }{100}

or,  \dfrac{s. p }{96.15} =  \dfrac{100 - 30 }{100}

Or,  \dfrac{s. p }{96.15} =  \dfrac{70}{100}

Or, s. p = \dfrac{70}{100} × 96.15

∴  s.p = $ 67.305

So, He will pay $ 67.30

Hence The money which Andre pay for the bike is $ 67.30  . Answer

B ) If the bike is discounted by 20 % , let The selling price = s.p'

So,

Discount % = \dfrac{m.p - s. p }{m . p}

or, 20 % = 1 - \dfrac{s. p' }{m . p}

or, \dfrac{20 }{100} = 1 - \dfrac{s. p' }{96.15}

Or, \dfrac{s. p' }{96.15} = 1 -  \dfrac{20 }{100}

or,  \dfrac{s. p' }{96.15} =  \dfrac{100 - 20 }{100}

Or,  \dfrac{s. p' }{96.15} =  \dfrac{80}{100}

Or, s. p' = \dfrac{80}{100} × 96.15

∴  s.p' = $ 76.92

So, He will pay $ 76.92

Hence The money which Andre pay for the bike is $ 76.92  . Answer

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