Let, the cost of a belt = x
cost of a wallet = y
Then, system of equations would be:
x + y = 42
7x + 4y = 213
Multiply 1st equation by 4,
4x + 4y = 168
Substitute it from 2nd equation,
3x = 45
x = 15
Now, substitute it in 1st equation,
15 + y = 42
y = 42 - 15 = 27
In short, Belt costs $15 and wallet costs $27
Hope this helps!
Answer:
He has 11 quarters
Step-by-step explanation:
* Lets study the information in the problem to solve it
- The value of dimes and quarters is $6.35
- There are dimes and quarters
- The dime = 10 cents
- The quarter = 25 cents
* We must change the money from dollars to cents
∵ $1 = 100 cents
∴ $6.35 = 6.35 × 100 = 635 cents
- The number of dimes = 3 + 3 × number of quarters
* Let number of dimes is D and number of quarter is Q
∴ D = 3 + 3Q
∴ 10D + 25Q = 635
* Substitute the value of D from first equation in the second equation
∴ 10(3 + 3Q) + 25Q = 635 ⇒ open the bracket
∴ 10(3) + 10(3Q) + 25Q = 635
∴ 30 + 30Q + 25Q = 635 ⇒ collect like terms
∴ 30 + 55Q = 635 ⇒ subtract 30 from both sides
∴ 55Q = 605 ⇒ divide both sides by 55
∴ Q = 11
* He has 11 quarters
Sum means add
the number is x
13 divided by a number is 13/x
the number divided by the number is x/13
so
also can be simplified to
or
translated it is
where x is the number
Answer:
Step-by-step explanation:
did you get the answers???
