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Gnom [1K]
3 years ago
15

What is the vertex of a parabola having the equation y = –2(x – 5)2 + 7? Which direction does the parabola open?

Mathematics
1 answer:
Vika [28.1K]3 years ago
7 0

y = -2(x-5)^2 + 7

That's vertex form for a parabola y=a(x-p)^2+q and we read off vertex (p,q) as

Answer: Vertex (5,7)

The negative <em>a</em> tells us this is a downward opening parabola (upside down from the usual y=x^2. I remember CUP - Concave Up Positive; here <em>a </em>is negative so not a cup, instead concave <em>down.</em> The same rule applies to second derivatives in calculus so memorize it now and use it later.

Answer: downward

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(-y+5•3)+7.2y-9)=6.2y+n
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(-y+5x3)+(7.2y-9)=6.2y+n
(-y+15)+(7.2y-9)=6.2y+n
since you're adding the two parentheses, you don't need to have them there
-y+15+7.2y-9=6.2y+n
7.2y-y +15-9 =6.2y+n
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-n=-6
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