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gulaghasi [49]
4 years ago
9

Log2 (x+3)+log2 (x+3)=4

Mathematics
2 answers:
lord [1]4 years ago
8 0
Log2(x+3^2) = 4
2^4= (x+3)(x+3)
2^4= x^2 + 6x + 9
x^2 + 6x - 7
(x-1) (x+7)
X= 1, -7
Rina8888 [55]4 years ago
7 0
4log squared plus log (2)
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alex41 [277]

Answer:

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Step-by-step explanation:

y = mx + b where m = slope and b = y intercept

So

The slope of the line y = 3x - 1 is 3 , y intercept is -1

The slope of the line y = -6x - 10 is - 6 and y intercept is -10

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Klio2033 [76]

Given the system of equations. We have:

- For (5,0)

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\begin{gathered} 5(5)+4(0)=-1 \\ 25+0=-1 \\ 25\ne-1 \end{gathered}

Answer: No

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\begin{gathered} 5(-7)+4(-8)=-1 \\ -35-32=-1 \\ -67\ne-1 \end{gathered}

Answer: No

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\begin{gathered} 5(3)+4(-4)=-1 \\ 15-16=-1 \\ -1=-1 \\ \text{and} \\ 3(3)-2(-4)=-5 \\ 9+8=-5 \\ 17\ne-5 \end{gathered}

This is satisfied for the first equation but not for the second. Therefore it is not a solution to the system.

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\begin{gathered} 5(-2)+4(-2)=-1 \\ -10-8=-1 \\ -18\ne-1 \end{gathered}

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