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love history [14]
3 years ago
14

Part B Based on your construction, what do you know about ΔABD and ΔBCD?

Mathematics
1 answer:
Anna71 [15]3 years ago
7 0

Answer: they both describe figure.ABCD

Step-by-step explanation:

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Simplify the expression shown below: (a^3b^12c^2)^2(a^5c^2)^3(b^5c^4)^0
NemiM [27]
= a^21b^24c^10 
use the product rules for each set of () then multiply them together. when multiplying variables with exponents you just add them together like for a^3 * a^5 = a^8.     (a^3 b^12 c^2)^2 = (a^6 b^24 c^4)
4 0
3 years ago
Select the correct answer.
Usimov [2.4K]

Applying the law of sines, the approximate length of side YZ is: A. 15.7 units.

<h3>How to Apply the Law of Sines?</h3>

Law of sines is expressed as follows: x/sin X = y/sin Y = c/sin Z.

Given the following:

  • x (YZ) = ?
  • X = 32°
  • z = 24
  • Z = 180 - 32 - 94 = 54°

Plug in the values

x/sin 32 = 24/54

x = (sin 32 × 24)/sin 54

x ≈ 15.7 units.

Learn more about the law of sines on:

brainly.com/question/27174058

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4 0
1 year ago
Find the limit of the function by using direct substitution.
musickatia [10]
Lim x->1 (x^2+8x-2)

substitute x =1
= 1^2 +8(1)-2
= 1 +8 -2
= 7

So the limit = 7
5 0
3 years ago
#7) Solve 8c - 3c + 3 = 13.
nordsb [41]

Hello!

\large\boxed{c = 2}

8c - 3c + 3 = 13

Begin by combining like terms:

5c + 3 = 13

Subtract 3 from both sides:

5c + 3 - 3 = 13 - 3

5c = 10

Divide both sides by 5:

5c/5 = 10/5

c = 2.

6 0
3 years ago
A box contains 12 balls of which 5 are red, and 7 are blue. If 4 balls are drawn from the box, in how many ways can this be done
mash [69]

Answer:

175 ways

Step-by-step explanation:

5 balls are red, and 7 balls  are blue making a total of 12 balls.

4 balls are drawn from the box,

1 ball is red and 3  balls are blue out of the 4 drawn from the box.

We have to choose 1 ball from 5 red balls and 3 blue balls from 7 blue balls.

Since the order is not essential we use combinations to find out

5C1 * 7C3= 5*35 = 175 ways

6 0
3 years ago
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