The difference between the 6th term and the 9th term of the sequence is 135
<h3>How to determine the difference</h3>
Given that the nth term is;
3n² + 11
For the 6th term, the value of n is 6
Let's solve for the 6th term
= 3( 6)^2 + 11
= 3 × 36 + 11
= 108 + 11
= 119
For the 9th term, n = 9
= 3 (9)^2 + 11
= 3( 81) + 11
= 243 + 11
= 254
The difference between the 6th and 9th term
= 254 - 119
= 135
Thus, the difference between the 6th term and the 9th term of the sequence is 135
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Because we know x stays constant, draw a point on (0,5). then draw a line extending up and down from (0,5) indefinitely because no matter what y is, x always stays the same--5.
You can first take out an x^2 from each number , 3x^6 - 39x^4 + 108x^2 = x^2 ( 3x^4 - 39x^2 + 108) Then just factor and solve for the zero's of the equation
<h2>Answer :-</h2>
As we know that,
Pythagoras triplet
1) a² + b² = c²
Let
<h3>Hence, A can't be Pythagoras triplet</h3>
2) a² + b² = c²
<h3>Therefore, B can be Pythagoras triplet</h3>
3)a² + b² = c²
<h3>Hence, C can't be Pythagoras triplet</h3>
4) a² + b² = c²
<h3>Hence, D can't be Pythagoras triplet</h3>
<h2 /><h2>Therefore :-</h2>
Only B can be Pythagoras triplet.
Answer:
Area of a square = side * 4
Step-by-step explanation:
