Answer:
c. Dark Web
Explanation:
Surface web is also called visible web is a part of world wide web that can be easily searchable using search engines as its contents are indexed by the search engines such as Google and its contents are accessible by public using standard web browsers. So a is not a suitable choice.
Deep Web is called invisible web as it is not accessible or searchable to standard search engines like Google. Search engines cannot index the contents of these sites. However such sites do not requires specialized browsers to access. So b is not a suitable choice.
Dark Web: It is a part of Deep Web sites but it requires specialized software and browsers to access. These sites cannot be indexed and cannot be searchable through standard search engines. This is also called dark side of the world wide web darker which is frequently used by criminals, hackers, black markets, hit-men. Illegal activities on a massive level is takes place in the dark web such as access to stolen sensitive information, malware, drug trade and terrorist operations. These sites are temporary and keep changing addresses to lessen the risk of getting caught by govt agencies or security officials. So c is the suitable choice.
Crypto-Net is a kind of neural network which works with encrypted data which can make a prediction based on the data without disclosing the data and prediction to the 3rd party. So d is not a suitable option.
Answer:
B.
Explanation:
Based on the sampling methods provided in regards to the question it can be said that the method being used is called Simple Random. This refers to dividing the population into different group which are then chosen at random, giving each group an equal chance of getting chosen. Which is exactly what is going on in this scenario, as the day is divided into three parts and her mood is measured randomly during each part of the day.
Update your passwords frequently, delete unused accounts, and be diligent about who and what you give your most personal information to. Invest in tech that fits your lifestyle without offering further distractions.
Answer:
- def check_subset(l1, l2):
- status = False
- count = 0
- if(len(l1) > len(l2)):
- for x in l2:
- for y in l1:
- if x == y:
- count += 1
-
- if(count == len(l2)):
- return True
- else:
- return False
-
- else:
- for x in l1:
- for y in l2:
- if x==y:
- count += 1
-
- if(count == len(l1)):
- return True
- else:
- return False
-
- print(check_subset([1,4,6], [1,2,3,4,5,6]))
- print(check_subset([2,5,7,9,8], [7,8]))
- print(check_subset([1, 5, 7], [1,4,6,78,12]))
Explanation:
The key idea of this solution is to create a count variable to track the number of the elements in a shorter list whose value can be found in another longer list.
Firstly, we need to check which list is shorter (Line 4). If the list 2 is shorter, we need to traverse through the list 2 in an outer loop (Line 5) and then create another inner loop to traverse through the longer list 1 (Line 6). If the current x value from list 2 is matched any value in list 1, increment the count variable by 1. After finishing the outer loop and inner loop, we shall be able to get the total count of elements in list 2 which can also be found in list 1. If the count is equal to the length of list 2, it means all elements in the list 2 are found in the list 1 and therefore it is a subset of list 1 and return true (Line 10-11) otherwise return false.
The similar process is applied to the situation where the list 1 is shorter than list 2 (Line 15-24)
If we test our function using three pairs of input lists (Line 26-28), we shall get the output as follows:
True
True
False
