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Alenkinab [10]
3 years ago
11

1) Prompt the user to enter two words and a number, storing each into separate variables. Then, output those three values on a s

ingle line separated by a space. (Submit for 1 point) Enter favorite color: yellow Enter pet's name: Daisy Enter a number: 6 You entered: yellow Daisy 6
Computers and Technology
1 answer:
masya89 [10]3 years ago
7 0

Answer:

import java.util.Scanner;

public class TestClock {

   public static void main(String[] args) {

 Scanner in = new Scanner (System.in);

       System.out.print("Enter favorite color:");

 String word1 = in.next();

       System.out.print("Enter pet's name:");

 String word2 = in.next();

       System.out.print("Enter a number:");

 int num = in.nextInt();

       System.out.println("you entered: "+word1+" "+word2+" "+num);

   }

}

Explanation:

Using Java Programming language

  1. Import the Scanner class
  2. create an object of the scanner class
  3. Prompt user to enter the values for the variables (word1, word2, num)
  4. Use String concatenation in System.out.println to display the output as required by the question.

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A signal travels from point A to point B. At point A, the signal power is 100 W. At point B, the power is 90 W. What is the atte
11Alexandr11 [23.1K]

Answer:

Attenuation = 0.458\ db

Explanation:

Given

Power at point A = 100W

Power at point B = 90W

Required

Determine the attenuation in decibels

Attenuation is calculated using the following formula

Attenuation = 10Log_{10}\frac{P_s}{P_d}

Where P_s = Power\ Input and P_d  = Power\ output

P_s = 100W

P_d = 90W

Substitute these values in the given formula

Attenuation = 10Log_{10}\frac{P_s}{P_d}

Attenuation = 10Log_{10}\frac{100}{90}

Attenuation = 10 * 0.04575749056

Attenuation = 0.4575749056

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7 0
3 years ago
An array is sorted (in ascending order) if each element of the array is less than or equal to the next element .
Aleks04 [339]

Answer:

// The program below checks if an array is sorted or not

// Program is written in C++ Programming Language.

// Comments are used for explanatory purpose

//Program Starts here

#include<iostream>

using namespace std;

//Function to check if the array is sorted starts here

int isSorted(int arr[], int count)

{

// Check if arrays has one or no elements

if (count == 1 || count == 0) {

return 1;

}

else

{

// Check first two elements

if(arr[0] >= arr[1])

{

return 0; // Not sorted

}

else

{ // Check other elements

int check = 0;

for(int I = 1; I<count; I++){

if (arr[I-1] > arr[I]) { // Equal number are allowed

check++; // Not sorted

}

}

}

if(check==0)

return isSorted(arr, count - 1); //Sorted

else

return 0; // Not sorted

}

// Main Method starts here

int main()

{

int count;

cin<<count;

int arr[count];

for(int I = 1; I<=count; I++)

{

cin>>arr[I-1];

}

int n = sizeof(arr) / sizeof(arr[0]);

if (isSorted(arr, n))

cout << "Array is sorted";

else

cout << "Array is not sorted";

}

8 0
3 years ago
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