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alukav5142 [94]
3 years ago
9

Given three floating-point numbers x, y, and z, output x to the power of y, x to the power of (y to the power of z), the absolut

e value of x, and the square root of (xy to the power of z). Ex: If the input is 5.0 6.5 3.2, the output is: 34938.56214843421 1.2995143401732918e+279 5.0 262.42993783925596 Hint: Coral has built-in math functions (discussed elsewhere) that may be used.
Computers and Technology
1 answer:
Angelina_Jolie [31]3 years ago
3 0

Answer:

float x

float y

float z

x = Get next input

y = Get next input

z = Get next input

Put RaiseToPower(x, y) to output

Put "\n" to output

Put RaiseToPower(x, RaiseToPower(y, z)) to output

Put "\n" to output

Put AbsoluteValue(x) to output

Put "\n" to output

Put SquareRoot(RaiseToPower(x*y, z)) to output

Explanation:

The first three lines of code is simply declaring the data type of the x, y and z variables which was declared as float type meaning number with decimal points.

The next three lines after the first three lines is getting the input from the user

In coral, we use Put <expression> to output to display <expression> to the console

For the first Put statement, I am telling the interpreter to display the value of x raised to the power of y to the console by using Coral's RaiseToPower built-in math function

The Put "\n" to output statement scattered in the snippet is just for formatting reasons so that each result will be displayed in a newline

The next computation RaiseToPower(x, RaiseToPower(y, z)) is a bit nested but  it is actually doing this: x^{y^{z} }

The next computation is AbsoluteValue(x) is doing this |x|

And the final computation SquareRoot(RaiseToPower(x*y, z)) is doing this:

\sqrt{(xy)^{z} }

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Drag each statement to the correct location.
VMariaS [17]

Answer:

(a)\ 222_{10} = DE_{16} --- True

(b)\ D7_{16} = 11010011_2 --- False

(c)\ 13_{16} = 19_{10} --- True

Explanation:

Required

Determine if the statements are true or not.

(a)\ 222_{10} = DE_{16}

To do this, we convert DE from base 16 to base 10 using product rule.

So, we have:

DE_{16} = D * 16^1 + E * 16^0

In hexadecimal.

D =13 \\E = 14

So, we have:

DE_{16} = 13 * 16^1 + 14 * 16^0

DE_{16} = 222_{10}

Hence:

(a) is true

(b)\ D7_{16} = 11010011_2

First, convert D7 to base 10 using product rule

D7_{16} = D * 16^1 + 7 * 16^0

D = 13

So, we have:

D7_{16} = 13 * 16^1 + 7 * 16^0

D7_{16} = 215_{10}

Next convert 215 to base 2, using division rule

215 / 2 = 107 R 1

107/2 =53 R 1

53/2 =26 R1

26/2 = 13 R 0

13/2 = 6 R 1

6/2 = 3 R 0

3/2 = 1 R 1

1/2 = 0 R1

Write the remainders from bottom to top.

D7_{16} = 11010111_2

<em>Hence (b) is false</em>

(c)\ 13_{16} = 19_{10}

Convert 13 to base 10 using product rule

13_{16} = 1 * 16^1 + 3 * 16^0

13_{16} = 19

Hence; (c) is true

7 0
2 years ago
A spreadsheet contains the maximum weight and maximum height for fifty dog breeds. The breeds are located in rows, and the weigh
MrRa [10]

Answer:

a. Locate

Explanation:

Question options (obtained on the net):

a. Locate

b. Sort

c. Filter

d. Replace

Explanation:

The largest value of the weights of the dog breed in row 43 is the maximum weight of the dog breed in the row

The 'MAX' formula or the 'Autosum' tool can be used to give the largest value in a row, or column

To locate the maximum value in MS Excel, the ADDRESS and MATCH and MAX functions are combined and entered into the blank cell on the right, specifying the same range for the MAX and MATCH functions, and a '0' for the MATCH function as well as a '1' for the ADDRESS function as follows;

=ADDRESS(MATCH(MAX(A1:E1), A1:E1, 0), 1)

Therefore, to navigate to the maximum weight, Emily should use a <em>locate</em>(ing) tool navigate to the information on the spread sheet

8 0
3 years ago
Which numbering system is used for some network addresses, to describe colors
FromTheMoon [43]
Hexadecimal it describes locations in memory
5 0
3 years ago
2.24 Write the relevant Python expression or statement, involving a list of numbers lst and using list operators and methods for
miskamm [114]

Answer:

lst = [11, 603, 99, 7, 582, 1];

print("The index of the middle element: " + str(int(len(lst)/2)))

print("The middle element: " + str(lst[int(len(lst)/2)]))

lst.sort()

sorted_lst = lst.reverse()

print("The list in descending order: " + str(lst))

first_number = lst.pop(0)

lst.append(first_number)

print("New lst: "+ str(lst))

Explanation:

- Initialize a list

- Find the middle index, int(len(lst)/2)

- Find the middle element, lst[int(len(lst)/2)]

- Sort the list in descending order (First sort the list in ascending order than reverse it)

- Get the first element using <em>pop</em> method, and append it to the end using <em>append</em> method

- - - - -

a) 0 == 1 == 2 --> Always evaluates false

b) 2 + (3 == 4) + 5 == 7 --> Evaluates true

c) 1 < -1 == 3 > 4 --> Always evaluates false

3 0
3 years ago
9.10: Reverse ArrayWrite a function that accepts an int array and the array ’s size as arguments . The function should create a
AleksandrR [38]

Answer:

#include <iostream>

using namespace std;

int * reverse(int a[],int n)//function to reverse the array.

{

   int i;

   for(i=0;i<n/2;i++)

   {

       int temp=a[i];

       a[i]=a[n-i-1];

       a[n-i-1]=temp;

   }

   return a;//return pointer to the array.

}

int main() {

   int array[50],* arr,N;//declaring three variables.

   cin>>N;//taking input of size..

   if(N>50||N<0)//if size greater than 50 or less than 0 then terminating the program..

   return 0;

   for(int i=0;i<N;i++)

   {

       cin>>array[i];//prompting array elements..

   }

   arr=reverse(array,N);//function call.

   for(int i=0;i<N;i++)

   cout<<arr[i]<<endl;//printing reversed array..

   cout<<endl;

return 0;

}

Output:-

5

4 5 6 7 8

8

7

6

5

4

Explanation:

I have created a function reverse which reverses the array and returns pointer to an array.I have also considered edge cases where the function terminates if the value of the N(size) is greater than 50 or less than 0.

8 0
3 years ago
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