Will do first question of each concept only because the rest of the questions are the same concept (the same few repeat but whatever).
1. <em>Total angle = (n - 2) * 180 --> 4 * 180 = 360°</em>
<em>70 + 130 + 120 + θ = 360</em> --> 320 + θ = 360 --> θ = 40
4. Total angle =<em> (10 - 2) * 180</em> --> 8 * 180 = <em>1440</em>
<em>1440/10</em> = 144°
6. Interior: (n - 2) * 180 --> 10 * 180 = 1800
Exterior: 12 * 180 = 2160 --> 2160 - 1800 = 360
9. (n - 2) * 180 --> 3 * 180 = 540
90 + 90 + 150 + 160 + θ = 540 --> 490 + θ = 540 --> θ = 50
13. Interior: (n - 2) * 180 --> 2 * 180 = 360
Exterior: n * 180 - (n - 2) * 180 --> 180n - 180n + 360 --> 360 (always the same)
16. 7r + 4r + 8r + 5r = 360 --> 24r = 360 --> r = 15
Answer:
x = (d + b) / (2a - c)
Step-by-step explanation:
2ax-b = cx+d
2ax - cx = d + b
x (2a-c) = d + b
x = (d + b) / (2a - c)
Answer:
A) 
Step-by-step explanation:


*
** From what the problem said, we know that we selected the correct equation.
I am joyous to assist you anytime.
Answer:
0.0082 = 0.82% probability that he will pass
Step-by-step explanation:
For each question, there are only two possible outcomes. Either the students guesses the correct answer, or he guesses the wrong answer. The probability of guessing the correct answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
In this problem we have that:
.
If the student makes knowledgeable guesses, what is the probability that he will pass?
He needs to guess at least 9 answers correctly. So









0.0082 = 0.82% probability that he will pass
Answer:
D.
Step-by-step explanation:
Remember that the limit definition of a derivative at a point is:
![\displaystyle{\frac{d}{dx}[f(a)]= \lim_{x \to a}\frac{f(x)-f(a)}{x-a}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28a%29%5D%3D%20%5Clim_%7Bx%20%5Cto%20a%7D%5Cfrac%7Bf%28x%29-f%28a%29%7D%7Bx-a%7D%7D)
Hence, if we let f(x) be ln(x+1) and a be 1, this will yield:
![\displaystyle{\frac{d}{dx}[f(1)]= \lim_{x \to 1}\frac{\ln(x+1)-\ln(2)}{x-1}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%281%29%5D%3D%20%5Clim_%7Bx%20%5Cto%201%7D%5Cfrac%7B%5Cln%28x%2B1%29-%5Cln%282%29%7D%7Bx-1%7D%7D)
Hence, the limit is equivalent to the derivative of f(x) at x=1, or f’(1).
The answer will thus be D.