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2 years ago

Can i have some help with this question? will give brainliestω

Mathematics

1 answer:

svet-max [94.6K]2 years ago

4 0

Answer:

It would be the last one

Step-by-step explanation:

shows on the graph it started at 12 inches and you can see it go down every hour by 2.

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What is 5x÷6=20<br> Pls help I can't figure it out

grin007 [14]

Answer:

x= 24

Step-by-step explanation:

5x=20*6

x=120/5

x=24

Hope this helps! Plz mark as brainliest! :)

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2 years ago

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Which phrase best describes a certificate of deposit?

vfiekz [6]

Answer:

An account in which money must stay deposited for a certain amount of time.

Step-by-step explanation:

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2 years ago

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What are the independent and dependent variables in the relationship?

Sindrei [870]

w is the width and it is the independent variable. You can pick any positive whole number you want (within reason of course; you can't go to infinity or go beyond some set boundary). Whatever you picked for w, the expression 2w-5 will be dependent on it. So the length is dependent on the width.

For instance, if the width is w = 10 feet, then 2w-5 = 2*10-5 = 20-5 = 15 feet is the length. The choice of 10 feet for the width directly affects the length being 15 feet.

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2 years ago

The starting and stopping point for Amir’s run this morning are 0.5 inch apart on the map. If each inch on the map represents 3

Aleonysh [2.5K]

Amir ran 1.5 miles in the morning.

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2 years ago

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In an effort to estimate the mean of amount spent per customer for dinner at a major Lawrence restaurant, data were collected fo

larisa86 [58]

Answer:

The 99% confidence interval for the population mean is 22.96 to 26.64

Step-by-step explanation:

Consider the provided information,

A sample of 49 customers. Assume a population standard deviation of $5. If the sample mean is $24.80,

The confidence interval if 99%.

Thus, 1-α=0.99

α=0.01

Now we need to determine $z_{\frac{\alpha}{2}}=z_{0.005}$

Now by using z score table we find that $z_{\frac{\alpha}{2}}=2.58$

The boundaries of the confidence interval are:

$\mu-z_{\frac{\alpha}{2}}\times \frac{\sigma}{\sqrt{n} }\\24.80-2.58\times \frac{5}{\sqrt{49}}=22.96\\\mu+z_{\frac{\alpha}{2}}\times \frac{\sigma}{\sqrt{n} }\\24.80+2.58\times \frac{5}{\sqrt{49}}=26.64$

Hence, the 99% confidence interval for the population mean is 22.96 to 26.64

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3 years ago