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3 years ago

Describe a virus and how it's different from a cell?

Biology

1 answer:

lana [24]3 years ago

6 0

Answer: how a virus differs from a cell...

It doesn’t contain any kind of cytoplasm, cell wall, cell membrane, ribosome or mitochondrion.

It doesn’t have any sort of metabolic enzyme of its own. So, no nutrition system is seen.

It can’t reproduce itself, without any help of the host living cell.

It can be crystallized, centrifuged or diffused.

It doesn’t have any sort of somatic development.

Chemically, its just a fusion of protein and nucleic acid. So, this characters differ a Virus from a living cell.

Explanation:

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You place some red blood cells in a solution and observe that they swell and burst. you place some cells in another solution, an

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Hhbjhhhhhhhhhhhjjjjjjjjfreeee tay k247)(883’

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2 years ago

Which diagram correctly shows how heterozygous alleles are found on homologous chromosomes?

LenKa [72]

Answer:

the chromosome are found in the nucleus of a body cell in pair

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2 years ago

Divide 250g in the ratio 5:3:4

Rama09 [41]

Answer:

let the three parts be

5x + 3x + 4x = 250

so on adding

12x = 250

x = 20

so it will be divided into three parts as

5 × 20 = 100

3×20= 60

4×20 = 80

Explanation:

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3 years ago

Mention five reason why are usually involved in criminal activities

Jobisdone [24]

1 poverty
2 hunger
3 drugs
4 racism
5 mental problems
( im not that sure )

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3 years ago

small group of 100 people decide to isolate themselves from the world and move to a small and remote deserted island. Out of thi

irina [24]

Answer:

Frequency of p $= 0.684$

Frequency of p $= 0.316$

Number of individuals with homozygous dominant (AA) $= 47$

Number of individuals with heterozygous (Aa) $= 43$

Number of individuals with homozygous recessive (aa) $= 10$

Explanation:

Out of 100 people, 10 have albino skin (aa)

So, the frequency of homozygous recessive individuals $(q^{2})$ is $\frac{10}{100} = 0.1$

Now, q will be

$= \sqrt{q^{2} } = \sqrt{0.1} \\= 0.316$

As per Hardy Weinberg's equation -

$p + q = 1$

Substituting the value of q in above equation, we get -

$p + 0.316 = 1p = 1 -0.316\\p = 0.684$

Now the frequency of homozygous dominant (AA) will be

$p^{2} = 0.684^{2} \\= 0.467$

Hence, out of 100 people $0.467 * 100 = 46.7 or 47$ people are homozygous dominant (AA)

Like wise out of 100 people $0.1 * 100 = 10$ people are homozygous recessive (aa)

As per As per Hardy Weinberg's equation-

$p^{2} + q^{2} + 2pq = 1\\$

Substituting the values in above equation, we get -

$0.467 + 0.316 + 2pq = 1\\2pq = 1 -( 0.467+ 0.1)\\2pq = 0.433$

So, out of 100 people $0.433 * 100 = 43.3 or 43$ people are heterozygous (Aa)

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3 years ago