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Alona [7]
3 years ago
8

What is the midpoint of the segment shown below?

Mathematics
2 answers:
Nina [5.8K]3 years ago
4 0

Answer:

The answer would be A 2,5

Step-by-step explanation:

d1i1m1o1n [39]3 years ago
3 0

Answer:

A

Step-by-step explanation:

Calculate the midpoint using the midpoint formula

[ 0.5(x₁ + x₂ ), 0.5(y₁ + y₂ ) ]

with (x₁, y₁ ) = (- 1, 5) and (x₂, y₂ ) = (5, 5)

midpoint = [ 0.5(- 1 + 5), 0.5(5 + 5) ]

              = [ 0.5(4), 0.5(10) ] = (2, 5 ) → A

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Find the total area for the regular pyramid. T.A. xxx(sqr) + xx (sqr)x
N76 [4]
We are to solve the total area of the pyramid and this can be done through area addition. We first determine the area of the base using the Heron's formula.
                           A = √(s)(s - a)(s - b)(s - c)
where s is the semi-perimeter
                                 s = (a + b + c) / 2
 Substituting for the base,
                               s = (12 + 12 + 12)/ 2 = 18
                          A = (√(18)(18 - 12)(18 - 12)(18 - 12) = 62.35
Then, we note that the faces are just the same, so one of these will have an area of,
                                s = (10 + 10 + 12) / 2 = 16
                                  A = √(16)(16 - 12)(16 - 10)(16 - 10) = 48
Multiplying this by 3 (because there are 3 faces with these dimensions, we get 144. Finally, adding the area of the base,
                          total area = 144 + 62.35 = 206.35
5 0
3 years ago
Need help with this question!!
Mekhanik [1.2K]

the answer is Y=3X+3

8 0
3 years ago
Read 2 more answers
Convert the measurements 66,597 grams = how many kgs
Nuetrik [128]
Answer

66597 g

divide by 1000

66.597 kg
3 0
3 years ago
What is the range of the equation
a_sh-v [17]

The range of the equation is y>2

Explanation:

The given equation is y=2(4)^{x+3}+2

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

y=2 \cdot 4^{x+3}+2

This can be written as y=2^{1+2(x+3)}+2

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

x=2^{1+2(y+3)}+2

Solving for y, we get;

x-2=2^{1+2(y+3)}

Applying the log rule, if f(x) = g(x) then \ln (f(x))=\ln (g(x)), then, we get;

\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)

Simplifying, we get;

(1+2(y+3)) \ln (2)=\ln (x-2)

Dividing both sides by \ln (2), we have;

2 y+7=\frac{\ln (x-2)}{\ln (2)}

Subtracting 7 from both sides of the equation, we have;

2 y=\frac{\ln (x-2)}{\ln (2)}-7

Dividing both sides by 2, we get;

y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}

Let us find the positive values for logs.

Thus, we have,;

x-2>0

     x>2

The function domain is x>2

By combining the intervals, the range becomes y>2

Hence, the range of the equation is y>2

7 0
3 years ago
The person who answes my question can u stay because i have more thankyou
castortr0y [4]

Answer:

c. 60 mins

Step-by-step explanation:

12 * 5 = 60

15 * 4 = 60

5 0
3 years ago
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