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boyakko [2]
4 years ago
14

If a and b are both integers and b does not equal 0, then -(a/b) = (-a)/b = a/(-b) Choose two values for a and b. see if those v

alues make the equation true
Mathematics
1 answer:
kkurt [141]4 years ago
7 0

a=4 , b=3  These values make the equation true .

<u>Step-by-step explanation:</u>

Here we have , If a and b are both integers and b does not equal 0, then -(a/b) = (-a)/b = a/(-b) Choose two values for a and b. We need to find if those values make the equation true . Let's find out:

We have the following equation:

-(a/b) = (-a)/b = a/(-b) , Let a=4 , b=3 , So

⇒ -(a/b) = (-a)/b = a/(-b)

⇒ -\frac{a}{b} = \frac{-a}{b} = \frac{a}{-b}

⇒ -\frac{4}{3} = \frac{-4}{3} = \frac{4}{-3}

⇒ -\frac{4(-1)}{3} = \frac{-4(-1)}{3} = \frac{4(-1)}{-3}                   { Multiplying by -1 }

⇒ \frac{4}{3} = \frac{4}{3} = \frac{4}{3}

Therefore , These values make the equation true .

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What is the value of x in the equation 6(x +11)= -300?
Kay [80]

Answer:

-61

Step-by-step explanation:

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8 0
3 years ago
Suppose a certain home improvement outlet knows that the monthly demand for framing studs is 2,300 when the price is $4.77 each
pogonyaev

Answer:

p + 0.0001q = 5

Step-by-step explanation:

Data provided in the question:

When Price, p₁ = $4.77 ; Demand, q₁ = 2,300

and,

When Price, p₂ = 3,300 ; Demand, q₂ = 3,300

considering the above as the points on the line,

now, the general equation for a line is given as:

\frac{q_1-q}{p_1-p}=\frac{q_2-q_1}{p_2-p_1}

on substituting the respective values, we get

\frac{2,300-q}{4.77-p}=\frac{3,300-2,300}{4.67-4.77}

or

\frac{2,300-q}{4.77-p}=\frac{1000}{-0.1}

or

2,300 - q = -10,000(4.77 - p)

or

⇒ 2,300 - q = -47700 + 10,000p

or

⇒ 10,000p + q = 2300 + 47700

or

⇒ 10,000p + q = 50000

or

⇒ p + 0.0001q = 5

8 0
3 years ago
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