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Vanyuwa [196]
3 years ago
8

Niko got the jumbo ice cream cone at the Dutchess County Fair. The amount of ice cream can be modeled using a cone whose height

is 12 centimeters and radius of 4 centimeters. A hemisphere and then a full sphere of ice cream the same radius were loaded on top of the cone as shown. If there are 237 cubic centimeters in a cup and 320 calories per cup of ice cream, how many calories is this treat if the cookie cone itself has 85 calories?
Mathematics
2 answers:
motikmotik3 years ago
6 0
85 over 320 of a cup
Ksenya-84 [330]3 years ago
6 0

total volume of ice cream = 2/3 *pi *r^3 +  4/3 *pi *r^3=9 where r = 4

total volume of ice cream  = 401.92 cm ^3

calories in 237 cm ^ 3 of ice cream = 320

calories in 401.92 cm ^ 3 of ice cream = (320/237) * 401.92 = 542.67 calories

calories of cookie cone = 85


Total calorie of treat = 542.67 + 80 = 627.6767 calories

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The reliability of a two-component product if the components are in parallel is 0.99.

In this question,

The probability of failure-free operation of a system with several parallel elements is always higher than that of the best element in the system. Reliability can be increased if the same function is done by two or more elements arranged in parallel.

A system contains two components that are arranged in parallel, they are 0.95 and 0.80.

Therefore the system reliability can be calculated as follows

⇒ 1 - ( 1 - 0.95 ) × ( 1 - 0.80 )

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⇒ 1 - 0.01

⇒ 0.99

Hence we can conclude that the reliability of a two-component product if the components are in parallel is 0.99.

Learn more about reliability of components here

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erma4kov [3.2K]
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3 years ago
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At a fair, each person can spin two wheels of chance. The first wheel has the letters F, A, I, and R. The second wheel has the n
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Answer:

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Sample space:

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Step-by-step explanation:

The collection of all possible outcomes of a probability experiment forms a set that is known as the sample space.

1. There are four possible outcomes for the first wheel: F, A, I and R

2. There are three possible outcomes for the second wheel: 1, 2 and 3

So, the sample space is

\begin{array}{cccc}(F,1)&(A,1)&(I,1)&(R,1)\\(F,2)&(A,2)&(I,2)&(R,2)\\(F,3&(A,3)&(I,3)&(R,13)\end{array}

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vladimir2022 [97]

Answer:$90

Step-by-step explanation:

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or

$95-$65=$30

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