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2 years ago

How many solutions does the system have?Explain

1 answer:

6 0

There are NO SOLUTIONS.

Substitute the first equation for y in the second equation. You can see it does not work. 6 does not equal 8. Therefore there are no solutions.

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Choose the correct answers for (a) the total installment price, (b) the carrying charges, and (c) the number of months needed to

Dvinal [7]

90+40.50×24
=1,062

1,062−900
=162

900÷40.50
=23

5 0

2 years ago

Read 2 more answers

In a study of the impact of smoking on birth weight, researchers analyze birth weights (in grams) for babies born to 189 women w

kompoz [17]

Answer:

c. Smoking is associated with lower birth weights. When smokers are compared to nonsmokers, we are 95% confident that the mean weight of babies born to nonsmokers will be between 76.5 grams to 486.9 grams more than the mean birth weight of babies born to smokers.

Step-by-step explanation:

The difference in mean birth weights (nonsmokers minus smokers) is 281.7 grams with a margin of error of 205.2 grams with 95% confidence.

Then, we know that the 95% confidence interval is (76.5, 486.9)

$LL=M-MOE=281.7-205.2=76.5\\\\UL=M-MOE=281.7+205.2=486.9$

a. We are 95% confident that smoking causes lower birth weights by an average of between 76.5 grams to 486.9 grams.

False, it interprets the confidence interval as a probability for individual cases. The confidence interval is a range for the population mean.

b. There is a 95% chance that if a woman smokes during pregnancy her baby will weigh between 76.5 grams to 486.9 grams less than if she did not smoke.

False, it interprets the confidence interval as a probability for individual cases. The confidence interval is a range for the population mean.

c. Smoking is associated with lower birth weights. When smokers are compared to nonsmokers, we are 95% confident that the mean weight of babies born to nonsmokers will be between 76.5 grams to 486.9 grams more than the mean birth weight of babies born to smokers.

True.

d. With such a large margin of error, this study does not suggest that there is a difference in mean birth weights when we compare smokers to nonsmokers.

There is enough evidence, as the lower bound of the confidence is positive. This means that there is only a probability of 0.05/2=0.025 that the true mean weight difference is smaller than 76.5 grams.

6 0

2 years ago

Using the distributive property to find the product (y – 4)(y2 + 4y + 16) results in a polynomial of the form y3 + 4y2 + ay – 4y

Crank

Answer:

The answer to your question is a = 16

Step-by-step explanation:

Polynomial

(y - 4) (y² + 4y + 16)

Process

1.- Multiply y by each term of the polynomial

y(y² + 4y + 16) = y³ + 4y² + 16y

2.- Multiply -4 by each term of the polynomial

-4(y² + 4y + 16) = -4y² - 16y - 64

3.- Write both results

y³ + 4y² + 16y - 4y² - 16y - 64

In bold we notice that a = 16

8 0

2 years ago

Luisa works at a gift shop. She receives a bonus if she sells at least 20 balloon bouquets in a month. Which graph represents th

suter [353]

Do you have an image of the graphs

5 0

2 years ago

Read 2 more answers

The measurement of the height of 600 students of a college is normally distributed with a mean of

ioda

Answer:

Step-by-step explanation:

We let the random variable X denote the height of students of the college. Therefore, X is normally distributed with a mean of 175 cm and a standard deviation of 5 centimeters.

We are required to determine the percent of students who are between 170 centimeters and 180 centimeters in height.

This can be expressed as;

P(170<X<180)

This can be evaluated in Stat-Crunch using the following steps;

In stat crunch, click Stat then Calculators and select Normal

In the pop-up window that appears click Between

Input the value of the mean as 175 and that of the standard deviation as 5

Then input the values 170 and 180

click compute

Stat-Crunch returns a probability of approximately 68%

5 0

2 years ago