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kompoz [17]
3 years ago
10

How many solutions does the system have?Explain

Mathematics
1 answer:
valkas [14]3 years ago
6 0
There are NO SOLUTIONS.

Substitute the first equation for y in the second equation. You can see it does not work. 6 does not equal 8. Therefore there are no solutions.

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9/15 as a whole number
Airida [17]

Answer:

1 and 2/3 I think- I hope this helps

7 0
3 years ago
What are the steps to answer -3(2r+7)=3
kumpel [21]
-3(2r+7)=3
distribute -3
-6r-21=3
add 21 to both sides, this causes the 21 on the left to cancel itself out.
-6r=24
divide each side by -6, this causes the -6 on the left side to cancel itself out.
r=-4
3 0
3 years ago
Read 2 more answers
Isabella spends $4.87 on paintbrushes and paint. How many of each item does she buy? Explain how you found your answer
Rina8888 [55]

Answer:Answer: Isabella buys 2 paintbrushes and 3 jars of paint.

Step-by-step explanation:

Isabella can buy together 5 paintbrushes ( p ) and jars of paint ( p ) : j + p = 5, She can`t buy 4 items ( because 4 * $0.99 = $3.96 < $4.87 ) and she also can`t buy 6 items ( 6 * $0.95 = $5.70 > $4.87 ). So: p = 5 - j. Another equation is: 0.95 * ( 5 - j ) + 0.99 j = 4.87, 4.75 - 0.95 j + 0.99 j = 4.87; 0.04 j = 0.12; j = 0.12 : 0.04; j = 3, p = 5 - 3 = 2. We can prove it: 0.95 * 2 + 0.99 * 3 = 1.90 + 2.97 = 4.87.

(Hope this helps!!!!)

5 0
3 years ago
Với giá trị nào của r và s thì hạng của A bằng 2
Norma-Jean [14]

Answer:

Please explain it in English

6 0
2 years ago
Y=x² + 16x + 64
motikmotik

I'll do the first one to get you started

The equation y = x^2+16x+64 is the same as y = 1x^2+16x+64

Compare that to y = ax^2+bx+c and we see that

a = 1

b = 16

c = 64

Use the values of 'a' and b to get the value of h as shown below

h = -b/(2a)

h = -16/(2*1)

h = -8

This is the x coordinate of the vertex.

Plug this x value into the original equation to find the corresponding y value of the vertex.

y = x^2+16x+64

y = (-8)^2 + 16(-8) + 64

y = 0

Since the y coordinate of the vertex is 0, this means k = 0.

The vertex is (h,k) = (-8, 0)

---------------------

So we found that a = 1, h = -8 and k = 0

Therefore,

f(x) = a(x-h)^2 + k

f(x) = 1(x-(-8))^2 + 0

f(x) = (x+8)^2

is the vertex form

---------------------

<h3>Final answer to problem 1 is f(x) = (x+8)^2 </h3>
8 0
3 years ago
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