Answer:
Step-by-step explanation:
Theorm-The Fundamental Theorem of Algebra: If P(x) is a polynomial of degree n ≥ 1, then P(x) = 0 has exactly n roots, including multiple and complex roots.
Let's verify that the Fundamental Theorem of Algebra holds for quadratic polynomials.
A quadratic polynomial is a second degree polynomial. According to the Fundamental Theorem of Algebra, the quadratic set = 0 has exactly two roots.
As we have seen, factoring a quadratic equation will result in one of three possible situations.
graph 1
The quadratic may have 2 distinct real roots. This graph crosses the
x-axis in two locations. These graphs may open upward or downward.
graph 2
It may appear that the quadratic has only one real root. But, it actually has one repeated root. This graph is tangent to the x-axis in one location (touching once).
graph 3
The quadratic may have two non-real complex roots called a conjugate pair. This graph will not cross or touch the x-axis, but it will have two roots.
For this case, the first thing we are going to do is define the following variable:
x = unknown number
We now write the following inequality:
5-3x <= 11
We clear x:
5-11 <= 3x
-6 <= 3x
-6/3 <= x
-2 <= x
The solution set is:
[-2, inf)
Answer:
the solution set is:
[-2, inf)
Answer:
-3/2.
Step-by-step explanation:
To find the slope, we find the rise over run.
In this case, the rise is 6 - 3 = 3.
The run is 3 - 5 = -2.
The slope is 3 / (-2) = -3/2.
Hope this helps!
0.12 = 12/100 = 6/50 =3/25
0.12 =3/25
The work is included if needed
A secant of a curve is a line that intersects the curve at a minimum of two distinct points.
So the answer is D. XY
