Jeremy is 5 years younger than his older sister. His older sister is 9 years older than his younger sister. The total of their a
ge is 49. Write and solve an equation to find the ages of Jeremy and his sisters.
I need help please!
2 answers:
Jeremy=x
Older sister=x+5
younger sister=x+5-9 or x-4
x+(x+5)+(x-4)=49
combine like terms
3x+5-4=49
3x+1=49
subtract 1 from both sides
3x=48
divide both sides by 3
x=16
Jeremy=16
Older sister=16+5=21
younger sister =16-4 or 16+5-9=12
J=16
OS=21
YS=12
Jeremy - x
Older sister - x+5
Younger sister - x-4
3x+1=49
3x=48
X= 16
Jeremy: 16
Older sister: 21
Younger sister: 12
You might be interested in
Yes here is an example:_
x/4 + 5/6 = 2
The LCD of 4 and 6 is 12 but we can also multiply through by 24 to clear the fractions:-
x/4 * 24 + 5/6 * 24 = 2 + 24
6x + 20 = 40
This will give us the same result if we multiplied through by 12.
They will not ever have the same amount because Adele is most likely $50 ahead of Kent each time.
Answer:
x=9
Step-by-step explanation:
Since x+5=14, then you would subtract 5 from 14. 14-5=9. So that means x equals 9.
Answer:
y = (5/9)x + 2
Step-by-step explanation:
Slope intercept form is
y = mx + b then plug in the values
y = (5/9)x + 2
Answer:
1.14
Step-by-step explanation:
3/10/3.8
=3/10×3.8
=0.3×3.8
=1.14
pls mark brainliest
