Answer:
should be 21
Step-by-step explanation:
Please, write "x^3" for "the cube of x," not "x3." "^" denotes exponentiation.
Then you have g(x) = x^3 - 5 and (I assume) h(x) = 2x - 2.
1) evaluate g(x) at x = -2: g(-2) = (-2)^3 - 5 = -8 - 5 = -13
2) let the input to h(x) be -13: h(-13) = 2(-13) - 2 = -28 (answer)
ANSWER:
4th option: y = cosine (x + pi)
STEP-BY-STEP EXPLANATION:
For the function y = cosine (x), when x = 0, y = 1 and when x = , y = -1. The graph shows the opposite, when x = 0, y = -1 and when x = , y = 1, so we must add the same amount x = , for y to be positive 1.
So the equation of the graph would be:
The correct answer is then the 4th option y = cosine (x + pi)
This is infinity solutions -
33x-33+99=33x-33-99
99=-99
Since 99 __equal -99 the equation has many solutions
1st quartile (25%) and the 3rd quartile (75%) values are -0.6745 and 0.6745 respectively. Use this formula z= (x-mean)SD -0.6745 = (x-25.3)/6.5.
x=25.3 - 0.6745(6.5) = 25.3 - 4.3843 = 20.9157 1st Quartile
0.6745 = (x - 25.3) 6.5
x = 25.3 + 0.6745 = 25.3 + 4.3843 = 29.6843 3rd quartile
interquartile range is the difference between the 1st quartile and the 4th quartile
