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3 years ago

11

Write an equation and solve. One telephone company charges $16.95 per month and $0.05 per minute for local calls. Another compan

y charges $22.95 per month and $0.02 per minute for local calls. For what number of minutes of local calls per month is the cost of the plans the same?
A. 16.95 + 0.05m = 22.95 + 0.02m; 200 min

B. 16.95 + 0.05m + 22.95 + 0.02m = 0; 570 min

C. 16.95 + 0.05m = 22.95 + 0.02m; 2 min

2 answers:

frutty [35]3 years ago

6 0

16.95+.05x=22.95+.02x

Subtract .02x from each side and subtract 16.95 from each side

.03x=6
Divide by .03

x=200 minutes.

Your answer is A

jarptica [38.1K]3 years ago

3 0

Answer:

The correct option is A. 16.95 + 0.05m = 22.95 + 0.02m; 200 min

Step-by-step explanation:

Consider the provided information.

One telephone company charges $16.95 per month and $0.05 per minute for local calls.

Let m is represents the number of minutes.

Therefore, the cost of plane can be represent as:

$16.95+0.05m$

Another company charges $22.95 per month and $0.02 per minute for local calls.

Therefore, the cost of plane can be represent as:

$22.95+0.02m$

Now equate both the equations:

$16.95+0.05m=22.95+0.02m$

$16.95+0.03m=22.95$

$0.03m=22.95-16.95$

$0.03m=6$

$m=200$

For 200 minutes the cost of both plans remains the same.

Hence, the correct option is A. 16.95 + 0.05m = 22.95 + 0.02m; 200 min

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