When 2 molecules of pyruvate from glycolysis enters the mitochondria,
2 molecules of CO2 are released
Answer:
The reaction isn't yet at equilibrium. The overall reaction will continue to move in the direction of the products.
Assumption: this system is currently at 
.
Explanation:
One way to tell whether a system is at its equilibrium is to compare its reaction quotient 
with the equilibrium constant 
of the reaction.
The equation for is quite similar to that for . The difference between the two is that requires equilibrium concentrations, while can be calculated even when the system is on its way to equilibrium.
For this reaction,
![\displaystyle Q = \rm \frac{[CS_2]\cdot [H_2]^{4}}{[CH_4]\cdot [H_2S]^{2}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Q%20%3D%20%5Crm%20%5Cfrac%7B%5BCS_2%5D%5Ccdot%20%5BH_2%5D%5E%7B4%7D%7D%7B%5BCH_4%5D%5Ccdot%20%5BH_2S%5D%5E%7B2%7D%7D)
.
Given these concentrations,
![\displaystyle Q = \rm \frac{[CS_2]\cdot [H_2]^{4}}{[CH_4]\cdot [H_2S]^{2}} =\frac{1.51\times (1.08)^{4}}{1.15\times (1.20)^{2}} \approx 1.72](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Q%20%3D%20%5Crm%20%5Cfrac%7B%5BCS_2%5D%5Ccdot%20%5BH_2%5D%5E%7B4%7D%7D%7B%5BCH_4%5D%5Ccdot%20%5BH_2S%5D%5E%7B2%7D%7D%20%3D%5Cfrac%7B1.51%5Ctimes%20%281.08%29%5E%7B4%7D%7D%7B1.15%5Ctimes%20%281.20%29%5E%7B2%7D%7D%20%5Capprox%201.72)
.
The question states that at , 
. Assume that currently this system is also at . (The two temperatures need to be the same since the value of depends on the temperature.)
It turns out that 
. What does this mean?
- First, the system isn't at equilibrium.
- Second, if there's no external changes, the system will continue to move towards the equilibrium. Temperature might change. However, eventually will be equal to , and the system will achieve equilibrium.
In which direction will the system move? At this moment, 
. As time proceeds, the value of will increase so that it could become equal to . Recall that is fraction.
When the value of increases, either its numerator becomes larger or its denominator becomes smaller, or both will happen at the same time. However,
- Concentrations on the numerator of are those of the products;
- Concentrations on the denominator of are those of the reactants.
As time proceeds,
- the concentration of the products will increase, while
- the concentration of the reactants will decrease.
In other words, the equilibrium will move towards the products.
<h2><u>
Answer:</u></h2>
C: They should try to reproduce Dr. Maxwell's research to verify his results
<h2><u>
Why?</u></h2>
Other scientists may or may not agree to Dr. Maxwell, so they should test Dr. Maxwell's research again to see if his conclusion is true or not.
Hope this helps!
