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ehidna [41]
3 years ago
5

Henry is in the community investigating sources of chemical energy for his science experiment. Select the best examples of chemi

cal energy Henry can use.
A gas station and people playing hopscotch
A squirrel eating acorns and a fire burning
Someone reading a book and eating a sandwich
Someone sliding down the slide and someone drinking water
Chemistry
2 answers:
djverab [1.8K]3 years ago
8 0
B it seems as a fire is better then the rest
Julli [10]3 years ago
6 0

Explanation:

Determine whether the following symbols are universal or contextual. In "The Nightingale and the Rose,"

Oscar Wilde uses a red rose as a symbol for love. In To Kill a Mockingbird, Harper Lee uses a mockingbird as a symbol for innocence.

In A Little Princess, Frances Hodgson Burnett uses hot buns as a symbol for the connection between the main character and a poor street child.

In "The Water of Life," the Brothers Grimm use water as a symbol for life.

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2Fe + 6HCl -> 2FeCl3 + 3H2 If 7.0 moles of HCl is added to enough iron that the HCl is completely used up, how many
DENIUS [597]

Answer: 3.5 moles of hydrogen gas will be produced.

Explanation:

The balanced chemical equation is:

2Fe+6HCl\rightarrow 2FeCl_3+3H_2

As HCl gets completely used up, HCl is the limiting reagent.

According to stoichiometry :

6 moles of HCl produces =  3 moles of H_2

Thus 7.0 moles of  HCl produces=\frac{3}{6}\times 7.0=3.5moles  of H_2

 Thus 3.5 moles of hydrogen gas will be produced.

3 0
3 years ago
What is the entropy change for the freezing process of 1 mole of liquid methanol at its freezing temperature (–97.6˚C) and 1 atm
Rudiy27

Answer : The value of change in entropy for freezing process is, -18.07 J/mol.K

Explanation :

Formula used :

\Delta S=\frac{\Delta H_{freezing}}{T_f}

where,

\Delta S = change in entropy

\Delta H_{fus} = change in enthalpy of fusion = 3.17 kJ/mol

As we know that:

\Delta H_{fus}=-\Delta H_{freezing}=-3.17kJ/mol=-3170J/mol

T_f = freezing point temperature = -97.6^oC=273+(-97.6)=175.4K

Now put all the given values in the above formula, we get:

\Delta S=\frac{\Delta H_{freezing}}{T_m}

\Delta S=\frac{-3170J/mol}{175.4K}

\Delta S=-18.07J/mol.K

Therefore, the value of change in entropy for freezing process is, -18.07 J/mol.K

4 0
3 years ago
If a vessel at this temperature initially contains pure sulfur trioxide and if the partial pressure of sulfur trioxide at equili
inessss [21]

Answer: 2 SO2 (g) + O2 (g) Kp = 7.69 If a vessel at this temperature initially ... and if the partial pressure of sulfur trioxide at equilibrium is 0.100 atm,

Explanation:

6 0
2 years ago
Which of the following statements is true about an endergonic reaction? ∆G is positive ∆G is negative ∆S is negative
Mazyrski [523]
The answer is the first option, <span>∆G is positive.</span><span> </span><span>Endergonic reaction is a chemical reaction where the Gibbs free of energy is positive and there is abosrption of energy. It is a nonspontaneous reaction or unfavorable reaction.</span>
8 0
3 years ago
The possible products of a double displacement reaction in aqueous solution are SrSO4 and NaCl. Which of these possible products
madam [21]

Answer:

SrSO4

Explanation:

According to solubility rules, we know that the sulphates of the elements of group two are insoluble in water. The solubility rules describe what chemical species are soluble in water and what species are not soluble in water.

Generally, all chlorides are soluble in water with exception of chlorides such as silver chloride. The chlorides of group one elements are usually highly soluble in water.

Since SrSO4 is a sulphate of a group two element (strontium) it will be the insoluble solid product of the double displacement reaction described in the question.

7 0
3 years ago
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