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Mrac [35]
2 years ago
9

A mixture of Oxygen and Hydrogen occupies a pressure of 101.3kPa. The pressure of Hydrogen is 56kpa. Calculate the pressure of o

xygen.
Chemistry
1 answer:
Anni [7]2 years ago
7 0

Answer:

45.3 KPa

Explanation:

From the question given above, the following data were obtained:

Total pressure (Pₜ) = 101.3 KPa

Pressure of Hydrogen (Pₕ) = 56 KPa

Pressure of Oxygen (Pₒ) =?

The pressure of oxygen in the mixture can be obtained as follow:

Pₜ = Pₕ + Pₒ

101.3 = 56 + Pₒ

Collect like terms

101.3 – 56 = Pₒ

Pₒ = 45.3 KPa

Thus, the pressure of oxygen in the mixture is 45.3 KPa

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1. A gas having the following composition is burnt under a boiler with 50% excess air.
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The composition of the stack gas are :

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C_3H_8 = 0.0202

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<h3 /><h3>What is a mole fraction?</h3>

The ratio of the number of moles of one component of a solution or other mixture to the total number of moles representing all of the components.

Assuming 100 g of the stack gas. Calculate the mass of each species in this sample according to their percentages.

Mass of CH_4 : 70% of 100 g = 70 g

Mass of C_3H_8 : 15% of 100 g = 15 g

Mass of CO : 15% of 100 g = 15 g

Now calculate the number of moles of each species:

Number of moles of CH_4 : \frac{70 g}{16.04 g/mol} = 4.3 mole

Number of moles of C_3H_8: \frac{15 g}{144.1 g/mol} = 0.10 mole

Mass of CO : \frac{15 g}{28.01 g/mol} = 0.53 mole

Now to calculate the mole fraction of each we use the formula:

Mole fraction of CH_4: \frac{4.3}{4.935} = 0.8713

Mole fraction of C_3H_8 : \frac{0.10}{4.935} = 0.0202

Mole fraction of CO : \frac{0.53}{4.935} = 0.107

Hence, composition of the stack gas are:

CH_4 = 0.8713

C_3H_8 = 0.0202

CO = 0.107

Learn more about mole fraction here:

brainly.com/question/13135950

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