Answer:
Explanation:
duehgjvcujhyeq bvckjfdsaeb gjdksghUIBGREQWMNHGTRE BAGTFEQA
Answer:
b. In equilibrium with the liquid phase, the pressure exerted by a gas.
Explanation:
When a liquid is warmed up to a temperature , it starts vaporising . The liquid is turning into gas and gas is turning into liquid at different rates . Initially the rate of former is higher but gradually the difference of rate between them decreases to zero . At this point the rate of conversion of liquid into gas and rate of conversion of gas into liquid becomes equal . This is called dynamic equilibrium point .
If we change the temperature , the equilibrium gets disturbed .
At this point the pressure exerted by the gas is called the vapour pressure of the liquid .
So option b ) is correct .
<em>mC: 12g/mol</em>
12g ------- 6,02·10²³ a.
6g --------- X
X = (6×<span>6,02·10²³)/12
</span><u>X = 3,01·10²³ atoms</u>
---->>> A :)
Answer:
tetrafluorochlorate
Tetrafluorochlorate(1-)
PubChem CID60211070Molecular FormulaClF4-Synonymstetrafluorochlorate(1-) tetrafluoridochlorate(1-) F[Cl](F)(F)F ClF4(-) CHEBI:30125 More...Molecular Weight111.45 g/molDatesModify 2021-01-09 Create 2012-10-18
Explanation:
please mark me as brainliest thank you
Answer:
Explanation:
Hello there!
In this case, according to the Henderson-Hasselbach equation, it is possible to write:
![pH=pKa+log(\frac{[A^-]}{[HA]} )](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%28%5Cfrac%7B%5BA%5E-%5D%7D%7B%5BHA%5D%7D%20%29)
Next, since we are given the pH and the [A–]/[HA] ratio, we can solve for the pKa as shown below:
![pKa=pH-log(\frac{[A^-]}{[HA]} )](https://tex.z-dn.net/?f=pKa%3DpH-log%28%5Cfrac%7B%5BA%5E-%5D%7D%7B%5BHA%5D%7D%20%29)
Now, we plug in the values to obtain:
Next, Ka is:
Best regards!
