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3 years ago

Helppp!!!! plz :-((

Chemistry

2 answers:

Mashutka [201]3 years ago

6 0

<h2><u>Answer:</u></h2>

C: They should try to reproduce Dr. Maxwell's research to verify his results

Other scientists may or may not agree to Dr. Maxwell, so they should test Dr. Maxwell's research again to see if his conclusion is true or not.

Hope this helps!

PIT_PIT [208]3 years ago

3 0

C. they should try to reproduce dr. maxwells research to verify his results !!

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(a) The original value of the reaction quotient, Qc, for the reaction of H2(g) and I2(g) to form HI(g) (before any reactions tak

Taya2010 [7]

Answer:

Here's what I get

Explanation:

Assume the initial concentrations of H₂ and I₂ are 0.030 and 0.015 mol·L⁻¹, respectively.

We must calculate the initial concentration of HI.

1. We will need a chemical equation with concentrations, so let's gather all the information in one place.

H₂ + I₂ ⇌ 2HI

I/mol·L⁻¹: 0.30 0.15 x

2. Calculate the concentration of HI

$Q_{\text{c}} = \dfrac{\text{[HI]}^{2}} {\text{[H$_{2}$][I$_{2}$]}} =\dfrac{x^{2}}{0.30 \times 0.15} = 5.56\\\\x^{2} = 0.30 \times 0.15 \times 5.56 = 0.250\\x = \sqrt{0.250} = \textbf{0.50 mol/L}\\\text{The initial concentration of HI is $\large \boxed{\textbf{0.50 mol/L}}$}$

3. Plot the initial points

The graph below shows the initial concentrations plotted on the vertical axis.

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3 years ago

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Answer:

faster, and the ingredient will be a liquid.

Explanation:

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. Using the pH scale below what would be the pH value of an Acid? *

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Answer : The pH value of an acid is below 7.

Explanation :

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Mathematically,

$pH=-\log [H^+]$

When the pH less than 7 then the solution is acidic and the concentration of hydrogen ion is greater than hydroxide ion.

When the pH more than 7 then the solution is basic and the concentration of hydrogen ion is less than hydroxide ion.

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Part A: How many moles of NH3 can be produced from 21.0 mol of H2 and excess N2?

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Answer:

a) 7.0 moles of NH3

b) 61.2 g of NH3

c) 4.15 g of H2

d) 8.9 ×10^19 molecules

Explanation:

Equation of the reaction;

N2(g) + 3H2(g) ⇄NH3(g)

If 3 moles of H2 yields 1 mole of NH3

21 moles of H2 will yield 21 × 1 /3 = 7.0 moles of NH3

1 mole of N2 yields 17 g of NH3

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If 6g of H2 produces 17 g of NH3

xg of H2 will produce 11.76 g of NH3

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Okay... what are the following

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