The answer should be D. 70%.
Hopefully that helps! :)
Answer: 0.0228
Step-by-step explanation:
Given : The mean and the standard deviation of finish times (in minutes) for this event are respectively as :-

If the distribution of finish times is approximately bell-shaped and symmetric, then it must be normally distributed.
Let X be the random variable that represents the finish times for this event.
z score : 

Now, the probability of runners who finish in under 19 minutes by using standard normal distribution table :-

Hence, the approximate proportion of runners who finish in under 19 minutes = 0.0228
Tzw uzv in the diagram bellow is a rectangle
<span>A
football team lost 5 yards on each 3 plays.
Let’s use a number line to be able to see how far in the field did they lost in
3 games.
=> 1 : 5 (1 game is to 5 yards)
=> 3 : 15 (3 games is to 15 yards )
All in all they lost 15 yards in 3 games.
pls. see attachment for more presentation.</span>