The function p(x)=x(x-5)(x-2)(x+3) has four zeros. what is the smallest zero?

1 answer:

5 0

To find the zeroes, you want to find what x is equal to when y=0. So we would set the function equal to 0 and solve for x

0=x(x-5)(x-2)(x+3)
x=0 x+5 x+2 x=-3

Therefore, the smallest zero is -3

Hope this helps

You might be interested in

Right trapezoid WXYZ is shown. Right trapezoid W X Y Z is shown. Sides X Y and W Z are parallel. Angle W is 73 degrees and angle

Sladkaya [172]

Answer:

∠WXY = 107°

Step-by-step explanation:

In a trapezoid, adjacent angles are supplementary, meaning they add up to 180°. ∠W and ∠WXY are adjacent, so they are supplementary. 180° - 73° = 107°.

Another way to do this is to know that there are 360° in a trapezoid. This is a right trapezoid, so two of the angles are 90°. One angle is 73°. 90° + 90° + 73° = 253°. 360° - 253° = 107°.

I hope this helps :))

3 0

4 years ago

I need a tutor for Honors Geometry please! I am a Freshman!

Sophie [7]

$\begin{gathered} \text{Two sides are given the same} \\ \text{The }BD\text{ is common for both the triangle.} \\ so,\text{ the triangle is congruent.} \end{gathered}$

7 0

1 year ago

Need help due tmr pls!!b!!!!

8090 [49]

Please supload it again it’s black

5 0

3 years ago

A circular mirror has a circumference of 30 pi inches. What is the area of mirror?

Aleonysh [2.5K]

Answer:

Step-by-step explanation:

circumference = 2πr

2πr = 30π inches

$r=\frac{30\pi}{2\pi}=15in$

Area = πr² = π*15*15 = 225π square inches

6 0

3 years ago

2. The table below shows that the distance d varies directly as the time t. Find the constant of variation and the equation whic

Artemon [7]

<h2><u>Problem Solving</u>:-</h2>

2. The table below shows that the distance d varies directly as the time t. Find the constant of variation and the equation which describes the relation.

<h2><u>Solution</u>:-</h2>

Since the distance d varies directly as the time t, then d = kt.

Using one of the pairs of values, (2, 20), from the table, substitute the values of d and t in d = kt and solve for k.

$\sf{\rightarrow{d = kt}}$