Bernardo travels the same distance at 25mph as he does at 50mph. However, since 25mph is only half of 50 mph, he must travel twice as long at 25mph. If you call the time he traveled 50mph "t", then
<span>t+2t=3 </span>
<span>3t=3 </span>
<span>t=1 </span>
<span>This means he traveled 1 hour at 50mph. In this time, he traveled 50 miles. He traveled the same distance at 25mph, so his total distance was </span>
<span>50miles+50miles=100miles </span>
<span>so the round trip was 100 miles.</span>
Subtract the 2x and divide by -4. y=1/2x-2 or y=x/2-2
Answer:
y = 2x - 3
Yes, your answer is correct.
Step-by-step explanation:
First, find the slope of the two points by using the slope formula:
y2 - y1
m = -------------
x2 - x1
13 - 5
m = -------------
8 - 4
8
m = ------- = 2
4
To find the y-intercept, plug in values into the slope-intercept formula:
y = mx + b
Where m = slope and b= y-intercept. Use any one of the points. I'll be using (4,5):
5 = (2) (4) + b
5 = 8 + b
-3 = b
b = -3
So, putting everything into the slope intercept formula:
y = 2x - 3
Answer:
y = -1/3x + 3 2/3
Step-by-step explanation:
step 1. find the slope of the given line
y2-y1/x2-x1 2 - 4/ 3 + 3 = - 1 / 3
take the opposite of that and there is your slope
step 2. plug in the values to the following equation using the given point:
y - y1 = m ( x - x1 ) y - 4 = - 1/3 ( x + 1 )
step 3. solve for y
y-4 = -1/3(x+1)
-1/3(x) and -1/3(1) ----> y-4 = -1/3x-1/3
y-4+4 = -1/3x-1/3+4 ----> y = -1/3x + 3 2/3
<em>hope this helps. if you need more help lmk in the comments. i am in algebra two so you can trust me. Happy holidays</em>
The volume of a cone is

where r = radius and h = height. If the cone has a volume of 94.2 cm³ (I assume you didn't mean m³ because that would be ridiculously huge) and a height of 10 cm, we can plug these values into the formula to find the radius. Don't do any rounding.

Now we know that's going to be the radius of our <em>new </em>cone as well since we're keeping the diameter the same. The volume is going to be double 94.2 which is 188.4. Let's solve for the height.