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ryzh [129]
3 years ago
5

The equation of line m is y=ax+b. Which could be the equation of line n? (ttm)​

Mathematics
1 answer:
Karolina [17]3 years ago
4 0
Is there a photo attached ?
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A pot contains 25 ounces of soil. You use 4 1/4
Wewaii [24]

Answer: multiply 4 1/4 by 5 then see if you have enough .

Step-by-step explanation: multiply 4 1/4 by 5 because you have used 1 herb already so if you do that you could have enough in there to pot 5 .

6 0
3 years ago
maria works as a florist and worked for 8 hours last week and earned 98$ at that rate how much will she earn this weekend if she
olga_2 [115]

$171.50

$98 ÷ 8 = $12.25 per hour

$12.25 x 14 = $171.50

7 0
3 years ago
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Find the largest odd number that divides the product of 16*24*60 evenly
melisa1 [442]
Odd = odd × odd

Prime factor
<span>16*24*60
(4*4)(3*8)(6*10)
(2*2*2*2)(3*2*2*2)(3*2*5*2)

multiple all the odd prime factors together
3*3*5 = 45
</span>
6 0
3 years ago
Write a brief explanation on how to simplify radicals
MrMuchimi
2 ways: make a little divide tree based on how many times you can divide it. Like you have sqrt88 you know it can divide by 2. So its 2 and 44, and 44 can be broken to 2 and 22, then 2 and 11. 11 can’t be divided anymore.

Now choose numbers that are the same and pair them together. These go outside the radicand. You had three 2’s and one 11. So a 2 would go on the outside and the remaining 2 and 11 would be multiplied leaved 2sqrt22.

Another way is to divide by the highest squared number. Taking sqrt88 again. 4 would be the highest squared number. So 88 would be 4 and 22, then 2 and 11. Since you have a 4 which is a perfect square you put that squareroot outside. The inside would remain the same because it wouldn’t break down into perfect squares or pairs anymore. So that would be 2sqrt22.

5 0
3 years ago
Mr. Hayes has 11 straw bundles to use forr bedding in his horse stalls. What is the greatest number of stalls he can fill if eac
Svetllana [295]

Answer:

2 stalls

Step-by-step explanation:

Mr. Hayes has 11 straw bundles to use forr bedding in his horse stalls. What is the greatest number of stalls he can fill if each stall holds exactly 4 bundles

1 stall = 4 bundles

4 bundles = 1 stall

11 bundles = x

Cross Multiply

4x = 11

x = 11/4

x = 2 3/4 stalls

The greatest number of stalls he can build is 2 stalls

7 0
3 years ago
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