Answer:
4, 14, 14, 16
Step-by-step explanation:
<u>Key</u><u> </u><u>skills</u><u> </u><u>needed</u><u>:</u><u> </u><u>Casework</u><u>,</u><u> </u><u>Mean</u><u>,</u><u> </u><u>Median</u><u>,</u><u> </u><u>and</u><u> </u><u>Mode</u>
1) We start with 4 numbers _ _ _ _
2) We can determine two of the numbers by using the fact that the median is 14 and the mode is 14.
3) The numbers would have to be:
The 2nd one does not work because the last number would have to be a 6 to have a mean of 12, but the range would not be 12.
4) So, our numbers are _ 14 14 _
5) The two numbers add up to 20 (in order to have a mean of 12. If you subtract the bigger one by the smaller one, it will be 12.
6) We can make a system: saying x is the bigger number and y is the smaller number.
x + y = 20
x - y = 12
Add both and you will get 2x = 32 (since the y values cancel out).
7) divide by on both sides, and x = 16.
8) To find y, we can plug x back in to one equation:
16 + y = 20
y = 4
Our smaller number is 4 and our bigger number is 16.
9) Therefore the numbers are: 4, 14, 14, 16
<em>Hope</em><em> </em><em>you</em><em> </em><em>understood</em><em> </em><em>and</em><em> </em><em>have</em><em> </em><em>a</em><em> </em><em>nice</em><em> </em><em>day</em><em>!</em><em>!</em><em> </em><em>:</em><em>D</em>
