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Illusion [34]
3 years ago
12

Find the roots of the equation x^3-3x^2+x+5

Mathematics
1 answer:
leonid [27]3 years ago
5 0
First observe that x=-1 is a root of the equation. Use long division to divide x^3-3x^2+x+5 by x+1, we find that (x^3-3x^2+x+5)/(x+1)=(x^2-4x+5). Now we need to find the roots of x^2-4x+5.
x^2-4x+5=0, 
x^2-4x+4=-1,
(x-2)^2=i,
x-2=i or -1,
x=2+i or 2-i. 
The three roots are 2+i, 2-i, -1.
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Anyone good with math??
-Dominant- [34]
Yup! We're all pretty good here.
7 0
4 years ago
(4)(2) = (2)(4) what property is this out of commutative property , associative property, distributive property
Anna007 [38]

Answer:

Commutative property

Step-by-step explanation:

This is an example of the commutative property as its states that it is applicable in multiplication and addition where 2 numbers can switch places and give the same result in both situations.

(4)(2) = 8

(2)(4) = 8

7 0
3 years ago
Es 18 de junio de 1815, las tropas napoleónicas se encuentran justo adelante, tu eres el ingeniero en balística y el general Wel
Airida [17]

Answer:

89.1° or -1.4°  

Step-by-step explanation:

1. Location:

You are on the Mont-Saint-Jean escarpment, near the Belgian town of Waterloo.

The French troops are about 50 m below you and 1.2 km distant.

2. Finding the firing angle

Data:

R = 1200 m

u = 600 m/s

h = -50 m (the height of the target)

a = 9.8 m/s²

We have two conditions.

Horizontal distance

(1) 1200 = 600t cosθ

Vertical distance

(2) -50 = 600t sinθ - 4.9t²

Divide each side of (1) by 600cosθ.

(3) \, t =\dfrac{2}{\cos \theta}

Substitute (3) into (2)

-50 = 600t \sin \theta - 4.9t^{2} =  600 \left( \dfrac{2}{\cos \theta} \right ) \sin \theta - 4.9 \left( \dfrac{2}{\cos \theta} \right )^{2}\\\\(4) \, -50 = 1200 \tan \theta - \dfrac{19.6}{\cos^{2} \theta}

Recall that

(5) sec²θ = 1/cos²θ = tan²θ + 1

Substitute (5) into (4)

-50 = 1200 \tan \theta - 19.6 \left(\tan^{2} \theta}+ 1\right )

Set up a quadratic equation

\begin{array}{rcl}-50 & = & 1200 \tan \theta - 19.6\tan^{2} \theta -19.6 \\0 & = & 1200 \tan \theta - 19.6\tan^{2} \theta + 30.4\\0 & =&19.6\tan^{2} \theta - 1200 \tan \theta - 30.4\\0 & =&\tan^{2} \theta - 61.224 \tan \theta - 1.551\\\end{array}

Solve for θ

Use the quadratic formula.

tanθ = 61.249 or -0.025

θ = arctan(61.249) = 89.1° or

θ = arctan(-0.025) = -1.4°

3 0
3 years ago
What is a formula for the nth term of the given sequence? 15,75,375​
spin [16.1K]

Answer:

3 × 5 ^ n

Step-by-step explanation:

since the series is exponential, the ratio between adjacent terms is 5.

nth term of geometric/exponential series is given by:

nth term = first term × (ratio)^(n-1)

= 15 × 5^ (n-1)

= 15 × 5^n × 5^-1

= 3× 5^n

7 0
3 years ago
I need help please and thanks
Akimi4 [234]
Perimeter of rectangle = all sides added
= 3+3+7+7 =20


volume of sphere = 4/3 x π x r(cubed)
= 4/3 x π X 4(cubed)
= 268.08257

area of triangle = base x height / 2
= 5 x 6 / 2
=30/2 =15

volume of pyramid = base height x base width x height / 3
= 300

side of triangle ---> use Pythagoras theorem so a(squared) + b (squared) = c(squared)
4(squared) + 3(squared) = c(squared)
16 + 9 = c(squared)
25 = c(squared)
c = 5


yw sis xoxoxo





7 0
3 years ago
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