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adell [148]
2 years ago
11

Which choice most effectively sets up the

Mathematics
1 answer:
tatiyna2 years ago
6 0

Option D. However, despite its many utilitarian benefits, colleges have not always supported the study of philosophy.

Which choice most effectively sets up the information that follows?

  • Despite philosophy teaching useful tools for academic and professional achievement, only 18 percent of the American colleges incorporated the course within curriculum, thus indicating their lack of support.
  • Hence, Option D is correct. The other  options do not express this condition.

To know more about reading comprehension, refer:

brainly.com/question/23343740

#SPJ4

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Can someone answer this?
Tcecarenko [31]
340.8 cm^2.

72+72+72+62.4+62.4=340.8cm^2.
6 0
3 years ago
Find the image (0,0) after two reflections first across y=3 and then across x-axis
Alina [70]
Refrection of point (0, 0) across y = 3 gives point (0, 6)
Refrection of point (0, -6) across the x-axis gives point (0, -6)
3 0
3 years ago
Read 2 more answers
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
Inga divided two identical rectangles into equal parts. She colored one part of each rectangle.
likoan [24]

Answer:

The areas are equal.

Step-by-step explanation:

Let the first rectangle be R and

the second rectangle be R'.

Sine R and R' are identical, their lengths are equal and their breadths are equal.

So, if Inga divided each into equal parts, then each part of both rectangles are equal.

Hence, the colored parts of both rectangles are equal.

8 0
3 years ago
Is 1/4 to the 0 power bigger then 1
marishachu [46]

Answer:

yes it is

Step-by-step explanation:

anything took to zerk is zero, 1 is higher thsn zero

4 0
2 years ago
Read 2 more answers
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