All categories

2 years ago

Which choice most effectively sets up the

1 answer:

tatiyna2 years ago

6 0

Option D. However, despite its many utilitarian benefits, colleges have not always supported the study of philosophy.

Which choice most effectively sets up the information that follows?

Despite philosophy teaching useful tools for academic and professional achievement, only 18 percent of the American colleges incorporated the course within curriculum, thus indicating their lack of support.
Hence, Option D is correct. The other options do not express this condition.

To know more about reading comprehension, refer:

brainly.com/question/23343740

#SPJ4

You might be interested in

If 2x^2 - 5x + 7 is subtracted from 4x^2 + 2x - 11, what is the coefficient of x in the result

WARRIOR [948]

Answer: 4 x 2 + 2 x - 11 = 2 x 2 - 5 x 7 + 0

Step-by-step explanation: The answer above

3 0

3 years ago

Read 2 more answers

Can somebody help please

FromTheMoon [43]

Answer:

a1 = -10

an = an-1 * -2

6 0

3 years ago

Is the answer 200? Or 4.5??? Or is none ? I don't know it's confusing :/ can I get help :/

skelet666 [1.2K]

Let x = the number of penguins we are finding

x ÷ 100 × 30 = 15
x = 15 ÷ 30 × 100
x = 50

hope this helps and have a great day :)

6 0

3 years ago

Read 2 more answers

How many solutions does the equation 3(x-5)-7=-3x8 have

LenaWriter [7]

Answer:

not really good at maths. 15.33

Step-by-step explanation:

3(x-5)-7=3×8

3x-15-7=24

3x =24+15+7

3x = 46

Three will divide it's self to give you one and divide 46 to give you 15.333

(correct me if i'm wrong)

8 0

3 years ago

Prove the divisibility of the following numbers:

Brut [27]

Answer:

Step-by-step explanation:

To prove divisibility, we need to factor the divident such that one of its factors matches the divisor.

(I use the notation x|y to denote that x divides y)

(A)

$75^{30}|45^{45}\cdot15^{15}\\45^{45}\cdot15^{15}=3^{45}\cdot 15^{45}\cdot 15^{15}=\\=3^{45}\cdot 15^{60}=3^{45}\cdot 15^{30}\cdot 15^{30}=3^{45}\cdot (3\cdot5)^{30}\cdot 15^{30}=\\=3^{45}\cdot 3^{30}\cdot(5\cdot 15)^{30}=3^{45}\cdot 3^{30}\cdot(75)^{30}\\\implies\\75^{30}|3^{45}\cdot 3^{30}\cdot75^{30}$

(B)

$72^{63}|24^{54}\cdot 54^{24}\cdot2^{10}\\24^{54}\cdot 54^{24}\cdot2^{10}=(2^{162}\cdot 3^{54})\cdot(2^{24}\cdot 3^{72}) \cdot 2^{10}\\=2^{196}\cdot 3^{126}$

In this case, it is easier to also factor the divisor to primes:

$72^{63}=2^{189}\cdot 3^{126}$

Both of these factor must be matched in the dividend in order to prove divisibility, and that indeed turns out to be true:

$2^{189}\cdot 3^{126}|2^{196}\cdot 3^{126}\implies\\2^{189}|2^{196}\,\,\mbox{and}\,\,3^{126}|3^{126}$

6 0

3 years ago